1. (t-5)^2 = 2(5-t)
2. 5/16x^2 = 5
2006-08-20 13:00:55 · 10 answers · asked by boycrazy42610 1 in Education & Reference ➔ Homework Help
1)
Start by squaring the left side:
(t-5)^2 = 2(5-t)
(t - 5)(t - 5) = 10 - 2t
t*(t - 5) - 5*(t - 5) = 10 - 2t
t^2 - 5t - 5t + 25
t^2 - 10t + 25 = 10 - 2t
t^2 - 8t + 15 = 0
Now factor:
(t - 3)(t - 5) = 0
t = 3 or 5
2) multiply each side by (16/5) to isolate x^2
(16/5)(5/16)x^2 = 5*(16/5)
x^2 = 16
x = +/- 4
2006-08-20 13:06:35 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Put them into the form ax^2 + bx + c = 0 and solve them using the quadratic formula:
x = (- b ± â(b^2 - 4ac))/2a
2006-08-20 20:11:28 · answer #2 · answered by Owlwings 7 · 0⤊ 0⤋
First rearrange the equation into the form:
ax^2 + bx + c = 0
Then try and factorise it, if you can't then use the quadratic formula (someone posted it above)
2006-08-20 20:07:44 · answer #3 · answered by Anonymous · 1⤊ 0⤋
1. (t-5)^2 = 2(5-t)
(t-5) (t-5) = (2)(5-t)
(t - 5) (-) = 2
(-1/2) ( t -5 ) = 0
t= 5
2006-08-20 20:18:08 · answer #4 · answered by goldmarble14 1 · 0⤊ 0⤋
1) t = 3 t = 5
2) t = +- 0.25
2006-08-20 20:12:37 · answer #5 · answered by fenx 5 · 0⤊ 0⤋
t^2-10=10-2t
t^2-2t-20=0
2006-08-20 20:07:22 · answer #6 · answered by Anonymous · 1⤊ 0⤋
Try going to Hotmath.com it has most textbooks avalible and can help you with your homework. And no i don't know how to do quadratic functions.
2006-08-20 20:05:51 · answer #7 · answered by horselover 2 · 0⤊ 2⤋
go to homeworkhelp.com and they have online tutors that can help you with this! Good Luck!
2006-08-20 20:07:43 · answer #8 · answered by Meriam W 2 · 0⤊ 1⤋
-b +- square root (b squared - 4ac). . .. all over 2a
2006-08-20 20:04:44 · answer #9 · answered by RoadKill 3 · 1⤊ 1⤋
Check out this website.... www.AskRose.org
Hopefully it will help you out!
2006-08-20 20:05:09 · answer #10 · answered by beck 2 · 0⤊ 2⤋