2006-08-20 13:00:22 · 6 answers · asked by Ryan 1 in Science & Mathematics ➔ Mathematics
Anything that fits:
a^2 + b^2 = r^2
Where "r" is the radius of a circle, centered about the origin.
2006-08-20 13:05:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a circle is defined by (X-h)^2 + (Y-k)^2 = R^2 ... a circle centered at point (h,k)....
as long as the formula is satisfied, the circle is "perfect" or...
if the radius of the circle is 13... there will exist a point on that circle with the coordinates of (5,12) and (12,5) ..which makes those points "perfect"
2006-08-20 20:13:02 · answer #2 · answered by Brian D 5 · 0⤊ 0⤋
http://www.math.clemson.edu/~simms/neat/math/pyth/
and a few hundred others for those of us knowing how to use a search engine âº
Doug
Errrmmmm.... Tulip.... That's true for **all** circles âº
2006-08-20 20:09:50 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
If the circumference divided by pi is equal to it's diameter, I think
2006-08-20 20:06:01 · answer #4 · answered by tulip70707 3 · 0⤊ 1⤋
Do you mean perfect squares?
2006-08-20 20:50:23 · answer #5 · answered by Benny 2 · 0⤊ 0⤋
i dont know
2006-08-24 19:56:03 · answer #6 · answered by Clarence A 2 · 0⤊ 0⤋