One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
2006-08-20 12:10:37 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
n+12 +2n=39
3n+12=39
-12=+12
3n= 51
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3n
n=17
17 2(11)= 22
sm la
2006-08-20 12:25:04 · answer #1 · answered by Phi nu 2 · 0⤊ 0⤋
Designate n=larger no., x=smaller no. So...n=12+x and x + 2n = 39
x + 2(12 + x) = 39
x + 24 + 2x = 39
3x + 24 = 39
Now subtract 24 from both sides,
3x = 15, x=5, and n=17.
Then check work!
2006-08-20 12:29:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋
number 1=x
number 2=x+12
x+2(x+12)=39
x= -3
2006-08-20 12:17:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x+12=y
(x+12)2y=39
solve for y.
2006-08-20 12:16:45 · answer #4 · answered by aSnxbByx113 2 · 0⤊ 0⤋