2006-08-20 11:59:59 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
my calculator is giving me ((5*sqrt of3)/22)+3/22. If that's the answer, how do I get there?
2006-08-20 12:21:16 · update #1
Given:
√3 /(5 - √3)
When you get the square root of a positive number you get two results, the plus and minus of the number.
Using the complex number approach you take the conjugate.
√3 /(5 - √3)
[√3 /(5 - √3)] * [(5 + √3)/(5 + √3)]
5√(3) + 3 / (25 + 5√3 - 5√3 - ( √3)² )
5√(3) + 3 / [25 - ( √3)² ]
5√(3) + 3 / (25 - 3)
(5√(3) + 3) / 22
That is:
0∙530011547 and - 0∙257284274
2006-08-20 12:41:33 · answer #1 · answered by Brenmore 5 · 0⤊ 0⤋
sq. root is the 35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70 skill. even with the undeniable fact that you won't be able to upload x^(a million/2) and squarert of x^(a million/2), you may simplify the first aspect: Write 35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70sq rt 35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70 as x^(a million/2)[35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70], notation for x^(a million/2) situations x^(a million/2) to the 35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70. To multiply powers you upload the e35c66a72bfbcff9f2d38d574768c9c70ponents, x^(a million/2) + 35c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70, so the e35c66a72bfbcff9f2d38d574768c9c70ponent of the first aspect is 335c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70 accordingly you get x^(a million/2) to the 335c66a72bfbcff9f2d38d574768c9c7035c66a72bfbcff9f2d38d574768c9c70 skill for the first aspect.
2016-11-26 20:21:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I assume that you want simplified in notation, not just an aproximation on a calculator.
sqrt(3) / [ 5 - sqrt(3) ]
multiply top and bottom by 5+sqrt(3)
[sqrt(3) ( 5+sqrt(3) ) ] / [ ( 5 - sqrt(3) ) * ( 5+sqrt(3) ) ]
[ 5*sqrt(3) + sqrt(3)*sqrt(3) ] / [ 5*5 - sqrt(3)*sqrt(3) ]
[ 5*sqrt(3) - 3 ] / [ 25 - 3 ]
[ 5*sqrt(3) ] / 22 + 3 / 22
This is then simplest terms with only one root and it's in the numerator.
2006-08-20 12:14:54 · answer #3 · answered by selket 3 · 0⤊ 0⤋
try:
sqrt(3) / (5 - sqrt(3) )
Use the complex conjugate or "5 - sqrt(3)" which is "5 + sqrt(3)"
Multiply the numerator and the denominator by the conjugate, and it will rationalize the denominator:
[sqrt(3)*(5 + sqrt(3) )] / [(5 + sqrt(3) )*(5 - sqrt(3) )]
[5sqrt(3) + 3] / [25 + 5sqrt(3) - 5sqrt(3) - 3]
=[5sqrt(3) + 3] [22
=[5sqrt(3)/22] + [3/22]
2006-08-20 14:23:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1) Take the square root of 3
2) Subtract the results of #1 from 5
3) Divide #1 results by #2 results
2006-08-20 12:06:03 · answer #5 · answered by Joe D 6 · 0⤊ 0⤋
If I'm not mistaken, the sq rt 3's cancel and you get 1/5.....like taking out the common denomonator.
2006-08-20 12:05:41 · answer #6 · answered by grrlgenius5173 2 · 0⤊ 2⤋
complete the square by multiplying by 1, in the form of (5 + sqrt3)/(5 + sqrt3)
the numerater will be 5*sqrt3 + 3
the denominator should be 5*5 -sqrt3* sqrt3 or simply 22
so you will have (5*sqrt3 + 3)/22
2006-08-20 13:08:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋
conjugate for denominator is 5 + root 3
top & bottom by conjugate gives you ..... 5root3 + 3 over 22 (25 - 3)
2006-08-20 12:10:42 · answer #8 · answered by Brian D 5 · 0⤊ 1⤋
type it in ur calc like that it should work
2006-08-20 12:04:29 · answer #9 · answered by suby 3 · 0⤊ 1⤋
1.732/5-1.732 = 1.732/3.268=.52998776...
2006-08-20 12:06:20 · answer #10 · answered by Anonymous · 0⤊ 0⤋