AC=BC/3
AC+BC=70
(BC/3)+BC=70
4BC/3=70
BC=(3*70)/4
BC=52.5 miles
AC+52.5=70
AC=70-52.5
AC=17.5 miles
:-)
2006-08-20 09:54:50
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answer #1
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answered by QuietFire 5
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AC = 17.5 miles
CB = 52.5 miles
Since C lines in a line between and and B and the distance from A to C is 1/3 the distance from C to B then lets call the AC distance X and the ditance CB 3X, making AB = 4X.
We already know that AB = 70 miles, so that means that X = 17.5 miles and thus 3X = 52.5 miles.
2006-08-20 16:58:21
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answer #2
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answered by mrjeffy321 7
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AC is one third of BC which means the whole line is divided into four portions, AC has one and BC has the remaining three. So simply: 70 / 4 = 17.5 thus AC is 17.5 miles and BC is 17.5 * 3 = 52.5 miles....
2006-08-20 16:58:05
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answer #3
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answered by Quasar 2
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the total sum would be 70 miles given the way you asked the question.
ac=1/3 of bc
bc=52.63
ac=17.37
given 1/3=.33
but hey this is just a guess ?
2006-08-20 17:02:31
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answer #4
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answered by darkmatter 3
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AC=17.5 miles
BC=52.5 miles
2006-08-20 17:03:11
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answer #5
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answered by falexge 2
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AC is 17.5 miles and BC is 52.5
2006-08-20 16:57:44
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answer #6
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answered by imsocool 2
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if A, B, and C lie along the same line then:
AC + BC = 70
AC = (1/3)BC so
(1/3)BC + BC = 70
BC = 52.5 miles
AC = 17.5 miles
2006-08-20 16:57:34
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answer #7
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answered by the redcuber 6
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AC = 17.5, BC = 52.5.
2006-08-20 16:55:19
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answer #8
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answered by Anonymous
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