2006-08-20 09:34:02 · 5 answers · asked by iluvunda559 1 in Education & Reference ➔ Homework Help
Find the prime factorization of each number:
57 = 3*19
228 = 2^2*3*19
The LCM is the product of each factor, taken to the highest power of each. Therefore, it is 2^2*3*19 = 228
2006-08-20 10:03:32 · answer #1 · answered by jenh42002 7 · 1⤊ 0⤋
Multiply 57 by 228 (57 x 228) and this will give you the least common multiple!@
2006-08-20 09:41:15 · answer #2 · answered by nswblue 6 · 0⤊ 3⤋
228=2x2x57
57=1x57
so L.C.M. of 228 and 57 = 57
2006-08-20 10:08:58 · answer #3 · answered by flori 4 · 0⤊ 0⤋
it's 228.
57*4 =228
228*1=228
(I accidentally left a good rating for brunette_grl, but her answer is incorrect.)
2006-08-20 09:45:58 · answer #4 · answered by q_midori 4 · 2⤊ 0⤋
456
2006-08-20 09:45:08 · answer #5 · answered by Anonymous · 1⤊ 3⤋