2006-08-19 23:49:15 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The relation, x^2 + y^2 = c is not a function. For a relation to be a function, one value of x must map to one value of y.
2006-08-20 00:00:57 · answer #1 · answered by prune 3 · 0⤊ 0⤋
You have probably been tought that a function is a relation for which each x is paried with only one y.
I like that definition, but in the math terminology used at college, what you call a "function" is called the "graph of the function".
But to answer your question: just take som function and mirror it in the x axis, for example
{(x,y)| y=sqrt(x) or y=-sqrt(x)}
is the plus/minus square root, a relation but not a function.
2006-08-20 06:59:14 · answer #2 · answered by helene_thygesen 4 · 0⤊ 0⤋
x^2 + y^2 = 25
This is a circle whose center is at the origin with radius five. Because there are two values of y for many, many of the x's, it is not a function although it is a relation
2006-08-20 08:01:08 · answer #3 · answered by MollyMAM 6 · 0⤊ 0⤋
y = sqrt x is not a function but a relation.
This is not a function because for every value of x, there are two values of y.
Also, y = sin inv. (x)
2006-08-20 08:30:10 · answer #4 · answered by nayanmange 4 · 0⤊ 0⤋
x > 3
where x is a variable.
This is not a function and is a mathematical relation.
2006-08-20 06:57:05 · answer #5 · answered by DG 3 · 0⤊ 0⤋
x^2 + y^2 = r^2 if u don't try to restrict the domain or the range
2006-08-20 08:04:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
y = x squared is a function
y = square root of x is not a function
2006-08-20 12:19:49 · answer #7 · answered by williamh772 5 · 0⤊ 0⤋
my uncle my daughter etc.
2006-08-23 23:32:35 · answer #8 · answered by walter_b_marvin 5 · 0⤊ 0⤋