SIMPLIFYING EXPRESSIONS: how can you simplify (1/x+h)-(1/x)?

Question

thnx for your help =]

Answer 1

if you mean: (1/(x+h))-(1/x) then :
(x-(x+h))/(x(x+h)) = (x-x-h)/(x^2+xh) =>
Result is: -h/(x^2+xh)

if you mean ((1/x)+h)-(1/x) then:
(1/x)-(1/x)+h =>
Result is : h

Answer 2

You can drop the parentheses, since these do not affect anything.

Normally, you would want to combine everything into one term, over a common denominator, which in this case would be "x". However, you don't have to do this in this case because the 1/x term and the -1/x term cancel each other out, meaning this simplifies to h.

(1/x+h)-(1/x) = 1/x+h-1/x = h

Answer 3

-1/x² - h/x

Answer 4

I'm guessing here.

(1/x+h) - (1/x)

Lose parentheses:
1/x + h - 1/x

Add terms with like denominators. That cancels out both 1/x to leave:

h

Haven't done math in a while so I could be wrong.

Edited: Just saw first answer. If that's what you meant then I'm wrong.

Answer 5

Assuming that what you wrote is correct, then
(1/x+h)-(1/x) = 1/x +h - 1/x = h (Note 1/x - 1/x will beocme 0)

Assuming you really meant 1/(x+h) - 1/x

= (x/x)(1/(x+h)) - ((x+h)/(X+h))(1/x) (that is I am trying to make the denominators equal for both parts)

= x/(x^2+xh) - (x+h)/(x^2+xh)

= -h/(x^2+xh) or -h/x(x+h)

Good luck.

Answer 6

(1/X+h)-(1/X)
1/X+h-1/X
=1/x-1/x+h
=h

Answer 7

I'm assuming you want the difference of 1/(x+h)-1/x
express both fractions with the common denominator (x+h)x and subtract them.

Answer 8

=h

(1/x+h) take away (1/x) leaves h

Example if "x" = 2 and "h" = 3
(1/2+3) - (1/2) = 3 or
(3.5) - (0.5) = 3

Answer 9

I'm assuming 1/x is one term and h is another.

1/x + xh/x - 1/x (Using LCD)
(1 + xh -1)/x = xh/x = h

Answer 10

1st multiply the whole equation by the LCD which is x(x+h). simplifying further, this will yield h.