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Could a number divided by zero be equal "infinity"? Could "infinity" multiplied by 'n' be equal "random"?

2006-08-19 09:57:05 · 12 answers · asked by PhiL& 2 in Science & Mathematics Mathematics

12 answers

dividing a non zero number by 0 is infinity or you can say its not well defined.
infinity multiplied by n is infinity only if n is a real number.

2006-08-19 10:17:01 · answer #1 · answered by flori 4 · 0 0

division by zero is not defined. however, consider you have a function y = 1 / x. as x approaches 0, x approaches a really small number which i can write ie x = 1 / z, where z is a really big number. so, y = 1 / (1 / z) so you get y = z, z being a really big number. so as x approaches 0, y approaches infinity. but you still cannot divide by zero!

for the second question, it all depends what n is. if n is any constant, n multiplied by infinity is infinity. but if n is not a fixed number (infinity also is not a fixed number), than t can be something else. consider y = x * (3 / x). here n is 3 / x. and when x approaches infinity, your product equals 3 (as it did the whole time). but it won't be random

2006-08-19 10:32:33 · answer #2 · answered by Bruno 3 · 2 0

zero is zero and infinity is way more than that, so no..You wouldn't want to divide by zero anyway, what would be the point? Infinity in theory cannot be mulitplied as it already contains everything so what else is there to add?

2006-08-22 17:05:11 · answer #3 · answered by Anonymous · 0 0

Approximately talking, the first answer is yes.Because zero is approximately something like 0.000000000000000000000001 for example.And if you divide one number with a number which is < 1,then the number increases as many times as it is less than 1.
I don't exactly know the other answer,but I think that the answer is "yes",because infinity can be got(approximately) by dividing any number with any other number like 0.0000000000000000...0003,
0.00000000000000000....8,
0.00000000000000000000.....n.
Sandra from Serbia,Europe

2006-08-19 10:13:32 · answer #4 · answered by sandra 2 · 0 1

Division by 0 is undefined. Trying to assign it a value leads to problems with other arithmetic operations, so it is not allowed.

Don't think of infinity as a number. That also leads to problems when you try to work it into normal arithmetic.

2006-08-19 10:10:35 · answer #5 · answered by rt11guru 6 · 1 0

Dividing by 0 is undefined, therefore x/0 has no solution. Suppose x/0 is defined, let x not= 0,
x/0 = y impllies x = y.0 = 0, a contradicition. therefore x/0 is not defined
Infinty is a special member of the set of extended real numbers, and is defined as follows:
x + inf(inity) = inf
inf + inf = inf
x - inf = -inf
-inf -inf = -inf
inf.x = inf (if x > 0) OR -inf (if x < 0)
-inf.x = -inf(if x > 0) OR inf(if x < 0)
inf.inf = inf
(-inf).(-inf) = inf

2006-08-19 10:18:54 · answer #6 · answered by hackmaster_sk 3 · 0 0

You can't divide by zero! It doesn't make sense

2006-08-19 10:02:27 · answer #7 · answered by Matthew H 3 · 0 0

You cant divide any numbers by zero....

2006-08-19 22:33:15 · answer #8 · answered by Anonymous · 0 0

The answer is still zero. You cannot divide something with nothing.

2006-08-19 10:05:27 · answer #9 · answered by just me 4 · 0 2

you can't divide a # by zero. It's IMPOSSIBLE!!!!!!!!!!!!!!!!!!!!!!!!!!

2006-08-19 11:54:05 · answer #10 · answered by Cutebruce88 2 · 0 0

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