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Bill finds an unusual object and wishes to calculate it's density. He discovers a problem of accurately weighing it, because it won't stay on the weighing pan. To solve this he adds the object to a beaker containing 75 mL of distilled water and finds the water level rises to 165 mL. The flask of water weighed 471 grams after the object was added. If the empty beaker weighed 277 grams, calculate the following

The weight of the water:______ g
The weight of the object:________ g
The volume of the object:_______ cm3
The density of the object:_________ g/cm3

2006-08-19 03:41:08 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

Understand that 1mL = 1cm^3.

Flask + Water + Object = 471g (given).
277g + 75g + Object = 471g
352 + Object = 471g
Object = 471g - 352g
Object = 119g (mass of object ).

Volume of Object = New Water volume - Old Water volume.
Volume of Object = 165ml - 75ml
Volume of Object = 90ml

Density of Object = Mass of Object / Volume of Object.
Density of Object = 119g / 90ml
Density of Object = 119g / 90cm^3
Density of Object = 1∙3222........cm^3

2006-08-19 04:07:26 · answer #1 · answered by Brenmore 5 · 1 0

And you are in AP Chemistry?

This problem is SO SIMPLE that my general chemistry students can solve it.

And YOU'RE IN AP CHEMISTRY???

You better transfer out quickly. You are just not up to the job.

2006-08-19 11:02:31 · answer #2 · answered by Alan Turing 5 · 0 0

You won't learn anything if you ask other to do your homework for you.

2006-08-19 12:29:46 · answer #3 · answered by cherox 3 · 0 0

sry i didnt learn that

2006-08-19 10:51:55 · answer #4 · answered by Prep♥™ 5 · 0 0

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