Program to find if a number is odd or even using bitwise operator in C?

Answer 1

if (Number & 0x1)
//number is odd
else
//number is even

Answer 2

ok.. both your previous posters got the logic right, but the syntax wrong
for a bitwise and operation use a single &
&& is used for logical anding

Answer 3

every odd number (in binary) has 1 on the end ie 10001 is odd.
so just do if (mynum && 1 == 1) odd
(mynum && 1 == 0) even

AND 1 will put all flags to zero except last one

Answer 4

When using C as the numeric 0 means boolean false at the same time you can use

if (num && 1) { /*odd here*/ } else {/*even here */}

Loren Soth

Answer 5

"%x" is used for representing unsigned ints. considering printf is a variadic function it calls for you to explicitly forged values to the properly perfect type like so: printf("%xn", (unsigned int) w); edit: genuinely, considering C makes few assumptions about the host ecosystem, it truly is more beneficial precise to imagine of the bitshift operators as mathematics operators. "a << b" Evaluates to "a" prolonged via "2 raised to the b'th ability" "a >> b" Evaluates to the quotient of "a" divided via "2 raised to the b'th ability"

Answer 6

main()
{
int x;
scanf("%d",&x);
if((x&1)==1)
printf("The number is odd");
else
printf("The Number is even");
}