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5x - 4y = -5
x - 2y = -7

2006-08-18 11:27:30 · 9 answers · asked by wicked 1 in Science & Mathematics Mathematics

9 answers

(3,5) is the pair of coordinates where the graphs of these two lines would meet.

2006-08-18 13:10:00 · answer #1 · answered by MollyMAM 6 · 0 0

x-2y=-7
x=-7+2y

5x-4y=-5
5(-7+2y)-4y=-5
-35+10y-4y=-5
6y=-5+35
6y=30
y=5

x=-7+2(5)
x=3

x = 3, y = 5

if you are young enough to NOT know this, you probably are not permitted to use yahoo! answers.

2006-08-18 11:40:58 · answer #2 · answered by Man 5 · 0 0

solve the equations

x - 2y = -7
is also: 2x - 4y = -14
subtract this and the first equation, you get

3x = 9
x = 3
solve for y; y = 5

2006-08-18 11:34:28 · answer #3 · answered by DG 3 · 1 0

x - 2y = -7
x = 2y - 7

5(2y - 7) - 4y = -5
10y - 35 - 4y = -5
6y - 35 = -5
6y = 30
y = 5

x = 2(5) - 7
x = 10 - 7
x = 3

ANS : (3,5)

2006-08-18 12:25:33 · answer #4 · answered by Sherman81 6 · 0 0

cchappa is real. you need to understand what it means incredibly than inquiring for suggestions. In any gadget of equations, what's needed is to discover values for the unknowns (that are the comparable in each and each equation) such that each and one and all the equations are real. interior the above case, you have the finest variety: simultaneous equations. nicely, i do no longer accept as true with the physique of techniques utilized via your math instructors (intersection, twist of fate or parallelism of strains) by way of fact it shows a sparkling loss of information. So how does one proceed? are you able to work out that in case you had one equation in one unknown, it would be elementary to sparkling up? it incredibly is step one. Secondly, each and each equation impacts the answer so each and each equation introduces its impact via changing variables in certainly one of the different equations. Thirdly, the approach is repeated until eventually we are waiting to sparkling up for all the unknowns. enable's see how this works for the above gadget: First, go with a variable (say y): y = -2x + 4 [a million] y = -x + 3 [2] If we go with the comparable fee for y interior the above equations, are you able to no longer see that it incredibly is only possible if the RHS (real hand facets) of [a million] and [2] are equivalent? so which you placed those equivalent and acquire: -2x + 4 = -x + 3 it incredibly is an equation in one unknown and hence elementary to sparkling up. answer is: x = a million. now you will discover y via changing x in any of the above equations. So y=2. you're becoming began out with x incredibly than y: x = (4 - y)/2 [3] x = 3 - y [4] Equating the RHS, we've: 2 -y/2 = 3 - y and fixing this for y: y/2 = a million So y=2. Now in structures with greater equations, the approach will become harder by way of fact there are greater variables in spite of the incontrovertible fact that it seems which you're nevertheless finding suggestions in terms of the coefficients and relentless words in each and each equation. enable's think your gadget of equations is: ay - bx = c [5] dy - ex = f [6] y = (bx + c)/a y = (ex + f)/d (bx)/a +c/a = (ex)/d + f/d => (bd-ea)x/(advert) = (af-cd)/(advert) => (bd-ea)x = (af-cd) => x = (af-cd)/(bd-ea) So a=a million, b=-2, c=4, d=a million, e=-a million and f=3 x = (a million*3 - 4*a million)/(-2*a million-(-a million*a million)) x = (-a million)/(-a million) = a million Get the belief? Now attempt this via finding a formulation for y!

2016-12-11 11:09:55 · answer #5 · answered by Anonymous · 0 0

x = -7 + 2Y
5 (-7 + 2Y) - 4Y = -5
-35 + 10Y - 4Y = -5
10Y - 4Y = -5 + 35
6Y = 30
Y=5


5X - 20 = -5
5x= 15
x = 3

2006-08-18 11:44:36 · answer #6 · answered by :) 2 · 0 0

x-2y=-7
x=-7+2y

5x-4y=-5
5(-7+2y)-4y=-5
-35+10y-4y=-5
6y=-5+35
6y=30
y=5

x=-7+2y=-7+2(5)
x=-7+10
x=3

(3,5)

2006-08-18 11:38:07 · answer #7 · answered by mim 3 · 0 0

x=3 and y=5 0r (3,5)

2006-08-18 11:41:23 · answer #8 · answered by Amar Soni 7 · 0 0

do your own homework

2006-08-18 11:33:56 · answer #9 · answered by Anonymous · 0 0

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