A coffee merchant has coffee beans that sell for $9 per
pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture
that will sell for $11.25 per pound. How much of each type of bean should be
used in the mixture?
2006-08-18 08:28:19 · 4 answers · asked by cupcake 1 in Education & Reference ➔ Homework Help
Let x = $9 coffee and y = $12 coffee, then
x + y = 100 and
9x + 12y = 100(11.25)
Solving the first equation for y you have
y = 100 - x
Replacing y with 100 - x in the second equation you have
9x + 12(100-x) = 100(11.25)
9x + 1200 - 12x = 1125
-3x = -75
x = 25 so y = 100 - 25 = 75
Answer: 25 pounds of the $9 coffee and 75 pounds of the $12 coffee.
2006-08-18 10:51:43 · answer #1 · answered by MsMath 7 · 2⤊ 0⤋
75 x 12=900
25x9 =225
1125.00/ 100= 11.25
2006-08-18 08:37:54 · answer #2 · answered by Generation268 3 · 1⤊ 2⤋
The correct answer to this question is the mixture should contain the minimum percentage of the better coffee required to make the product taste good enough that customers will buy it, but your algebra teacher will not accept that truth-full answer.
2006-08-18 09:33:16 · answer #3 · answered by Automation Wizard 6 · 2⤊ 2⤋
ooh! Algebra -
lets see
100 pounds of coffee at $11.25 per pound is $1125
so
1125 = 12x + 9y
just solve for x and y.
2006-08-18 08:34:50 · answer #4 · answered by Kutekymmee 6 · 3⤊ 3⤋