geometry please help?

Question

If you can get all of these correct first I will give you 10 points! Thanks!


1. Calculate the slope between the points (3, 7) and (-3, 7).

a. 0
b. 1/6
c. 6
d. undefined

2. Calculate the slope between the points (-6, 9) and (4, 11).

a. - 1/5
b. 1/5
c. 5

3. If line MN is the diameter of a circle with M(-3, -4) and N(-7, -14), find the center of the circle.

a. (-2, -5)
b. (-4, -10)
c. (-5, -9)
d. (-10, -18)

4. Where P is (-2, 6), R is (-10, 4), and segment is a diameter of P, find the coordinates of T.

a. (-4, 12)
b. (6, 8)
c. (8, 2)
d. (8, 6)

question 4 is messed up so you dont have to answer it.

Answer 1

1.(7-7)/(-3-3)=0
2.(11-9)/(4+6)=1/5
3.(-3-7)/2;(-4-14)/2=-5,-9
4.what is T

Answer 2

1. a.
2. b.
3. a.
4. You mis-typed the question.

These are all basic, basic questions. You need to study and show your work. Answers 1-3 are correct. I'll see you in class.


EDIT: I see some other answers for 3. The Correct answer for 3 is c. Folks, don't show all the work!

Answer 3

(1) a.
slope= change in y divided my change in x; so,
(7-7)/(-3-3)=(0)/(-6) = 0

(2) b.
Similar to (1)
(11-9)/(4-(-6))=2/10=1/5

(3) c.
diameter = (x1, y1) where x1=(M(x)+N(x))/2, y1=(M(y)+N(y))/2
x1=(-3-7)/2 = -5
y1=(-4-14)/2 = -9
Therefore, (-5,-9)

(4) b.
Solving for coordinates of T . . .
P(x)=(T(x)+R(x))/2 ~~> T(x) = 2P(x) - R(x)
P(y)=(T(y)+R(y))/2 ~~> T(y) = 2P(y) - R(y)

T(x) = 2(-2) -(-10) = -4+10 = 6
T(y) = 2(6) - (4) = 8
Therefore,
T is (6,8)

Answer 4

(1) Ans. a.
(2) Ans. b.
(3) Ans. c.
(4) You need to tell us a bit more about the problem. If P is a point at (-2,6) then 'a diameter of P' makes no sense. And what is 'T'?


Doug

Answer 5

1.)
m = (7 - 7)/(-3 - 3)
m = 0/(-3 + (-3))
m = 0/(-6)
m = 0

ANS : a.) 0

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2.)
m = (11 - 9)/(4 - (-6))
m = 2/(4 + 6)
m = 2/10
m = 1/5

ANS : b.) (1/5)

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3.)
M = ((-3 + (-7))/2),((-14 + (-4))/2)
M = (-10/2),(-18/2)
M = (-5,-9)

ANS : c.) (-5,-9)