3, 7, 10, 8, _, 9, 12, 16.
1, _, 27, 256, 3125, 46656.
2006-08-18 06:52:40 · 17 answers · asked by madan raj 1 in Science & Mathematics ➔ Mathematics
The 2nd one is 4
1^1 = 1, 2^2 = 4, 3^3 = 27, 4^4 = 256, etc.
No idea on the first one.
2006-08-18 07:00:16 · answer #1 · answered by sassy_91 4 · 1⤊ 0⤋
3, 7, 10, 8, 9, 9, 12, 16
1, 4, 27, 256, 3125, 46656
2006-08-18 14:01:15 · answer #2 · answered by bgrt 3 · 0⤊ 0⤋
1, 4, 27, 256, 3125, 46656
Answer: 4 (1^1, 2^2, 3^3, . . . , 6^6)
2006-08-18 14:01:16 · answer #3 · answered by daanzig 4 · 0⤊ 0⤋
For a) I don't know for sure because there's perhaps some interpretation involved. I'd guess 11 because then the difference between each term is then pallendromic (4, 3, -2, 3, -2, 3, 4).
For b) the missing term is 4 as the i-th term is i^i.
2006-08-18 15:21:21 · answer #4 · answered by Kyrix 6 · 0⤊ 0⤋
1.
2. n^n. 2^2 = 4
2006-08-18 14:04:58 · answer #5 · answered by cherox 3 · 0⤊ 0⤋
the second one is 4 because...
1=1
2 times 2=4
3 times 3 times 3=27
4^4=256
5^5=3125
etc.
2006-08-18 14:01:04 · answer #6 · answered by The Ghetto David Hume 3 · 0⤊ 0⤋
Looks like the answer for the first series is 7.
The answer for the second series is 3.
2006-08-18 14:01:05 · answer #7 · answered by sarge927 7 · 0⤊ 0⤋
Okay, for the first one is 7 and for the second it's 8
2006-08-18 14:01:47 · answer #8 · answered by sama 2 · 0⤊ 0⤋
The second series answer is 4.
2006-08-18 14:00:00 · answer #9 · answered by VampireDog 6 · 0⤊ 0⤋
#1=7
#2=i don't know
2006-08-18 13:59:30 · answer #10 · answered by annie 2 · 0⤊ 0⤋