2006-08-17 18:50:19 · 34 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You asked Bush for the answer?
2006-08-17 18:55:23 · answer #1 · answered by Anonymous · 1⤊ 1⤋
12+3=15 not 20
2006-08-17 19:04:47 · answer #2 · answered by Anonymous · 0⤊ 1⤋
12+3 = 20 because 20 = 12 + 3
2006-08-17 18:58:29 · answer #3 · answered by doolph2002 4 · 0⤊ 0⤋
In base 5, 12+3=20.
2006-08-17 18:57:32 · answer #4 · answered by knivetsil 2 · 3⤊ 0⤋
12+3=15 not 20
2006-08-17 18:54:58 · answer #5 · answered by Wan-yu Yeh 1 · 0⤊ 0⤋
As knivetsil has already said, 12 + 3 does in fact equal 20 in base 5.
In base ten the digit values go ((from right to left)
1, 10, 100, 1000, 10000, and so on
In base five the digit values go (from right to left)
1, 5, 25, 125, 625, and so on
So the equation 12 + 3 = 20 converted from base 5 into base 10 would read
(1 * 5) + (2 * 1) + (3 * 1) = (2 * 5) + (0 * 1)
5 + 2 + 3 = 10 + 0
10 = 10
2006-08-17 19:31:46 · answer #6 · answered by Pablo Fanques 3 · 0⤊ 0⤋
12+3=20 assume 3=A, A=8
12+A= 20?
2006-08-19 23:37:24 · answer #7 · answered by Anonymous · 0⤊ 0⤋
At base 5, 12 + 3 = 20
Because 12 in base 5 is 7 in decimal, and 3 in base 5 is 3 in decimal, and 20 in base 5 is 10 in decimal.
In decimal,
7 + 3 = 10
^_^
2006-08-18 01:30:11 · answer #8 · answered by kevin! 5 · 0⤊ 0⤋
+5
2006-08-17 18:56:11 · answer #9 · answered by Misanthropist 6 · 0⤊ 0⤋
12+3=20
you don't know.
2006-08-17 18:58:58 · answer #10 · answered by Anonymous · 0⤊ 0⤋
It depends on your definition of +.
In Z_{5}={[0],[1],[2],[3],[4]} with the binary operation: "addition modulo 5", [12] = [2] and [15]=[20] = [0]. It is standard practice to omit the brackets.
Here 12 + 3 = 0.
2006-08-17 20:26:24 · answer #11 · answered by king64_shahab 2 · 0⤊ 0⤋