2006-08-17 13:04:51 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hint: you need to figure out the slope of the new line from the old line and then you use a formula to find the equation of the line.
2006-08-17 13:09:57 · answer #1 · answered by raz 5 · 0⤊ 0⤋
slopes of parallel lines are the same so the parallel equation would be
y= -2x+b
to figure out b you would plug in the point
-1= -2 (-2)+b
multiply -2 x -2
-1= 4+b
subract 4 from both sides
-5=b
the final equation would be y= -2x-5
2006-08-17 13:14:32 · answer #2 · answered by Chrissy 2 · 1⤊ 0⤋
Y=-2x-5
2006-08-17 13:15:22 · answer #3 · answered by Mustang2008 2 · 0⤊ 0⤋
line parallel to y= -2x+3 is of the form
y= -2x+c
this passes through (-2,-1)
therefore -1 = (-2*-2) +c
or c = -5
therefore required equation is y= -2x-5
2006-08-17 14:53:10 · answer #4 · answered by qwert 5 · 0⤊ 0⤋
write the equation of the new line with same slope, unknown y-intercept, sub in your point, solve for b
chrissy, you ain't seen nothing yet...
2006-08-17 13:13:15 · answer #5 · answered by Michaelsgdec 5 · 0⤊ 0⤋