(t+1)^2 = (t+1)*(t+1)
Using the FOIL method:
= (t*t) + (t*1) + (t*1) + (1*1)
= t^2 + t + t + 1
= t^2 + 2t + 1
Now, do your own stinkin' home work...
2006-08-17 12:32:55
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answer #1
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answered by Filbert Crunchy 2
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(t+1)^2
=t+t+1+1
=t^2+2
2006-08-17 12:29:47
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answer #2
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answered by 7yes! 1
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(x+1)^2 turns into
(x + 1) (x + 1), which turns into (when foiled)
x^2 + 2x + 2
2006-08-17 12:33:33
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answer #3
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answered by Obama, 47 y/o political virgin 5
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(t+1)^2 = (t+1)(t+1) = t(t+1) + 1(t+1) = t^2+t*1+1*t+1*1= t^2 + 2t + 1
Easio.
Factor this: ((ax+b)^n)^(m)
2006-08-17 12:28:43
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answer #4
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answered by Duke 1
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good gosh ... what kinda schl r u in ???!!! genius schl who asks ?s like that ....... lol =0) good luck hun
2006-08-17 12:27:41
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answer #5
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answered by i luv penguins =0p 6
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= Pa1 ,a2 (x2(t+ 1)x1(t),x2(t)),
2006-08-17 12:29:09
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answer #6
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answered by cozmo 1
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