Did anyone see the Star magazine; said Angelia Jolie left Brad Pitt with the kids? Any truth to this rumor?
2006-08-17 12:22:13 · 9 answers · asked by lusaisthebest 3 in Entertainment & Music ➔ Celebrities
I doubt that Angelina and Brad broke up. Consider the source...not very reliable.
2006-08-17 12:37:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
They will most likely end up on the rocks. Angelina nor Brad are faithful and despite what she thinks she is a single mother. Marriage is the only thing that would change that. I dont care that she lives with the guy helping her with kids. I think that she is sick to want another kid already after recently giving birth. SHe is overzealous and a media whore
2006-08-17 12:51:28 · answer #2 · answered by Stephanie D 3 · 0⤊ 0⤋
i lose interest of listening to that Jennifer Aniston became at fault because she became not waiting to have babies. Why is all of it about what Brad needed besides? Jennifer had the right to do video clips, and if Brad were the supportive husband he ought to were, he might want to have stood via her. Brad might want to nevertheless have cheated on her with Angelina no matter if Jen had given him a baby. Face it. A cheater is a cheater, and if he will cheat on one better 1/2, it truly is going to take position back.
2016-11-05 01:19:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
considering the source it is definitely a rumor
2006-08-17 17:48:15 · answer #4 · answered by anonymous101 3 · 0⤊ 0⤋
Unfortunately, yes, they did. Poor kids...
2006-08-17 12:27:09 · answer #5 · answered by Anonymous · 1⤊ 0⤋
i hope so, they were weird together, he made a much better couple with jennifer
2006-08-17 12:46:55 · answer #6 · answered by chrystallec 4 · 0⤊ 0⤋
Oh, so boring Celebrity, yesterday, bye!!!
2006-08-17 12:37:47 · answer #7 · answered by GreatNeck 7 · 0⤊ 1⤋
i doubt it... at least the part about leaving her kids.
2006-08-17 12:34:50 · answer #8 · answered by lady sixx 6 · 0⤊ 1⤋
It is a rumor!!!!!!!!
2006-08-17 12:28:13 · answer #9 · answered by Anonymous · 0⤊ 2⤋