In 1983, Soviet Cosmonaut Valentin Lebedev set a space endurance record. He was aloft for 18,230,400 seconds. How long did his misson last
in mintutes?
In hours?
In days?
2006-08-17 11:41:29 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In minutes, divide the answer by 60.
In hours, divide the previous answer by 60.
In hours, divide the previous answer by 24.
I'm going to leave the arithmetic to you.
You can always set up a problem by thinking of the units, and making sure that "like units" (minutes to minutes, hours to hours) divide each other out, until you're left with the unit you're wanting; and then put the correct ratios (1 min/60 sec, or whatever applies to the problem) into place, and then all you have to do is work the numbers.
2006-08-17 11:53:41 · answer #1 · answered by jmskinny 3 · 1⤊ 0⤋
First divide 18,230,400 by 60=303,840 minutes
Divide by 60 again=5,064 hours
Finally divide by 24=211 days
2006-08-17 19:10:14 · answer #2 · answered by Marla 6 · 0⤊ 0⤋
Well, x seconds is x-divided-by-60 number of minutes, so 3000 seconds is 50 minutes. To get the number of hours, divide the number of minutes by 60 again. To get the number of days, divide the number of hours by 24.
You should get a six-digit answer for the first question, a four-digit answer for the second question, and a three-digit answer for the third.
2006-08-17 18:49:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First , divide by 60 for 303,840 minutes
Then divide that answer by 60 for 5064 hours
Then divide that answer by 24 for 211 days
2006-08-17 19:16:51 · answer #4 · answered by MollyMAM 6 · 0⤊ 0⤋
There is 60 seconds in a minute so that would make it 303,840 minutes. There is 3600 secs in a hour so that would be 5064 hours. There is 86,400 secs in a day so that would be 211 Days!! I hope this helps
2006-08-17 18:53:34 · answer #5 · answered by Nessie H 2 · 0⤊ 0⤋
Just divide that number by 60 to get the minutes and divide your answer in minutes to get te hours and divide your answer in hours by 24 to get the days.
2006-08-17 18:48:54 · answer #6 · answered by HocusPocus 2 · 0⤊ 0⤋
take the seconds for mins divide by 60 then for hours divide by 60 again and take that # divide by 24 for days
2006-08-17 18:58:53 · answer #7 · answered by Anonymous · 1⤊ 0⤋
It depends on where the time was taken... In space the time just won't be the same.... so u will have to assume... time in space to be 1/17th of that on earth..... now the correctness of the stop watch needs to be gauged... for that we should use euler's theorem... which can measure correctness upto pica units.....
assuming correctness to be 10^-12 of the stop clock... and the distance between the observer and Valentin can be assumed to be 11 feet.....
Now with all this data in mind.... I think u can solve it from here....
2006-08-17 18:55:08 · answer #8 · answered by honey 3 · 0⤊ 1⤋
Divide by 60 for minutes, then by 60 again for hours, then by 24 for days.
If you don't have a calculator handy, your computer probably has one under "Accessories."
If we gave you the answer vs. showing you how, you wouldn't learn how to do math or think, then, would you?
2006-08-17 18:49:28 · answer #9 · answered by Anonymous · 0⤊ 0⤋
18230400/60=303840 minutes.
303840/60=5064 hours
5064/24=211 days
2006-08-17 20:43:18 · answer #10 · answered by Anonymous · 0⤊ 0⤋