If you're being asked to graph it on paper, then you'll be best off picking a few "landmark" numbers, and plugging them in for x, and see what value you get. Then try drawing it to match that general shape.
For example, when x=0, you have (0+5)^2-1 = (5^2-1) = 25-1 = 24. So it crosses the y-axis at 24.
To see where it crosses the x-axis, assume y = 0, and solve for x: (x+5)^2 = 1. Taking the square root of both sides, we have x+5 = 1, and x+5 = -1. These two come out to x = -4, and -6.
Since we know it's symmetrical, plug in -5 to find where it "bottoms out": (-5+5)^2-1 = (0)^2-1 = -1
So, we know that the bottom of the parabola is at (-5, -1), the arms going up cross the x-axis at (-6, 0) and (-4, 0), and the right side crosses the y-axis at (0, 24). With these landmarks, you should be able to sketch out the general shape. Show your work and label these points, and you should get full credit.
2006-08-17 11:44:24
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answer #1
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answered by jmskinny 3
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A parabola of the form
y = a(x - h)² + k
has a vertex at (h, k),
a vertical axis of symmetry at x = h,
and other attributes that can be gleaned by amplitude a.
In your equation,
y = (x + 5)² - 1,
the vertex is (-5, -1).
The axis of symmetry is x = -5.
Because the amplitude is positive (a = 1), your parabola will open upward and the vertex is the minimum point on the graph.
Other points on your parabola will include:
(-4, 0), (-3, 3), (-2, 8), (-1, 15), and by symmetry,
(-6, 0), (-7, 3), (-8, 8), (-9, 15).
2006-08-17 11:36:48
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answer #2
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answered by Anonymous
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How tough can Math be.... I think u will have to hyperbole a parabola.. in order to get to a linear equation and then for x=0 y=5.... now, this is not the end but just the beginning..... the straight line you have if you consider x+5 raise to 1 ( as in 2-1).... is nothing but a parabola.... where the line tends to curvature at infinity..........
For correct answer refer to coolmath.com .........
2006-08-17 11:50:37
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answer #3
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answered by honey 3
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for a graph, go to http://www.calculator.com/calcs/GCalc.html
type in (x + 5)^2 - 1, then click enter on the keyboard
2006-08-17 17:27:55
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answer #4
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answered by Sherman81 6
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Go to http://www.coolmath.com/graphit/index.html and then type in "(x=5)^2-1" without the quotes and hit enter.
2006-08-17 11:37:22
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answer #5
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answered by Eric R 1
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enter the equation online at http://www.coolmath.com/graphit/index.html its easy
2006-08-17 13:52:45
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answer #6
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answered by Anonymous
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That would be rather difficult to do here...
2006-08-17 11:30:57
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answer #7
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answered by Linduh. 3
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It would look roughly like this
...._
../....\
/........\
But curvier.
2006-08-17 11:35:41
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answer #8
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answered by Ox Cimarron 2
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wat grade r u? im only going to 9th....i have never seen that in my life! sorry
2006-08-17 11:33:42
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answer #9
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answered by Anonymous
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