energy of a charged capacitor?

Question

how can i find energy of a charged capacitor?give answer with explaination.

Answer 1

0.5 C V^2
C is Farads
V is volts
answer is Joules (a watt second)
A 10 farad capacitor charged to 12 volts holds
0.5 * 10 * 144 = 720 Joules

The 0.5 comes from the fact the voltage goes from 12 to 0 (end point or discharged) and the average power is 1/2 obviously.

Answer 2

The energy of a charged capacitor is given by the equation:

1/2 CV^2.

It results from integrating the power required to supply a current to the capacitor for a given amount of time. The 1/2 comes from the fact that there Must (yes, must) be a resistor in the circuit to charge the cap, and half the energy gets dissipated by that resistor.

Answer 3

dE/dt = P dE = P dt dE = IV dt dE = (C dV/dt) V dt dE = C V dV combine E = a million/2 CV^2 Now, when you consider that Q = CV, we are able to write this as E = a million/2 QV with any luck you are able to now see the place the a million/2 comes from. the reason it relatively is there is that that would charge wasn't all pushed onto the capacitor on the utmost voltage V. somewhat, it relatively is the cost Q expanded with the aid of the generic voltage over the charging era, V/2.

Answer 4

Energy stored in a charged capacitor equals

E=0.5*C*V^2, where C - capacity and V - voltage

or

E=0.5*((Q^2)/V), where Q is charge.

or

E=0.5*V*Q