A. 3.2.1
B. 15.3
C. 15.14.13
D. 15.14.12.3
2006-08-17 06:00:58 · 12 answers · asked by shahad 1 in Science & Mathematics ➔ Mathematics
C.
When the seats are empty, there are a total of 15 people that can posibly sit in there. We will only let 1 person sit on a chair.
When the 1st seat is taken there are now 14 people who can possibly sit on another chair. Same goes when 2 seaats are taken.
To find the total number of possibilities, we multiply together the possible number of people for seat 1, seat2, and seat 3.
Or, if we use stat, nPr = n! / (n-r)!
So:
15P3 = 15!/ (15-3)! = 15*14*13*12! / 12! = 15*14*13
2006-08-17 06:40:10 · answer #1 · answered by dennis_d_wurm 4 · 0⤊ 0⤋
c. The answer is really simple: There are 15 different people that are competing for 3 positions (say Pres, Vice Pres and Sec).
One person gets chosen, so there are 14 people left.
The second person is chosen, so there are now 13 people left.
thus you get 15*14*13
2006-08-17 07:38:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
C
15 * 14 *13
=2730
Unlike the girl above me, I am positive
2006-08-17 06:06:57 · answer #3 · answered by billyandgaby 7 · 0⤊ 0⤋
I see it's C
2006-08-17 06:19:34 · answer #4 · answered by Anonymous · 0⤊ 0⤋
u can put 15 in 1st place;then 1 is out leaving 14;u can put 14 in 2nd place leaving 13;u can put 13 in 3rd place which turns out 15*14*13 ie., C
2006-08-17 06:50:38 · answer #5 · answered by harsha_kadi 2 · 0⤊ 0⤋
Ans):- C
Prove):-
15P3 [here P refers to permutation]
=15!/(15-3)!
=15!/12!
=15.14.13
2006-08-17 06:14:34 · answer #6 · answered by Anonymous · 0⤊ 0⤋
C) dude, take statistics or something.
2006-08-20 04:35:42 · answer #7 · answered by chris m 5 · 0⤊ 0⤋
Answer (c)
Doug
2006-08-17 06:07:35 · answer #8 · answered by doug_donaghue 7 · 0⤊ 0⤋
i'm pretty sure it's B ... 45 ways.
2006-08-17 06:06:49 · answer #9 · answered by Natalie M 3 · 0⤊ 3⤋
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2006-08-17 06:15:34 · answer #10 · answered by omar g 2 · 0⤊ 0⤋