2006-08-17 04:28:48 · 17 answers · asked by CARMELO A 1 in Science & Mathematics ➔ Mathematics
648
2006-08-21 01:06:22 · answer #1 · answered by Joe Mkt 3 · 1⤊ 0⤋
Putting the value of the y in the equation, we get,
3^3(3^3-3)
=27(27-3)
=27*24
=648
2006-08-17 05:54:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I'm assuming y3 is "y to the 3rd power"
y^3(y^3-y)
3^3((3^3)-3)
27(27-3)
27*24
648
2006-08-17 04:36:33 · answer #3 · answered by DClegalaide 2 · 1⤊ 0⤋
if y=3 then y3(y3-y)
expanding the bracket we get:
y^2 9-y^2 3
substituing it in equation we get:
(3)^2*9-(3)^2*3
81-27
answer thus is 55
2006-08-17 04:43:29 · answer #4 · answered by payal m 2 · 0⤊ 0⤋
If I'm reading the function correctly
(3^3)(3^3 - 3) = 27*24 = 648
Doug
2006-08-17 04:34:53 · answer #5 · answered by doug_donaghue 7 · 1⤊ 0⤋
If y=3,then y^3(y^3-y)=(3)^3{ (3)^3 -3}
=27{27 -3}
= 27*24
=648
2006-08-17 04:44:09 · answer #6 · answered by Amar Soni 7 · 0⤊ 0⤋
54
2006-08-17 04:35:43 · answer #7 · answered by yofatcat1 6 · 0⤊ 1⤋
It's 54. Those who are saying six hundred something mistakenly thing you are asking about y to the third power instead of Y times three.
Go with 54. I have spoken.
2006-08-17 04:38:38 · answer #8 · answered by Anonymous · 0⤊ 0⤋
I'm assuming that those are cubes so it would be 27(27-3)=648.
2006-08-17 04:35:08 · answer #9 · answered by Anonymous · 1⤊ 0⤋
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2016-10-02 04:59:10 · answer #10 · answered by Anonymous · 0⤊ 0⤋