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An aeroplane is rising up with the speed 100m/s.at a moment a pecket is dropped from it which reaches the ground after 50 sec .calculate height of the aeroplane when the packet was dropped......

2006-08-17 04:11:15 · 8 answers · asked by THE FANTASY PRINCESS 2 in Science & Mathematics Physics

the ques is perfectly right...

2006-08-17 04:21:25 · update #1

WELL...
none of u r wright...
but still CIRIC u got a BIT CLOSER TO THE RIGHT METHOD THOUGH...the answer is not at all affected by the gravity increase..

2006-08-19 03:24:27 · update #2

8 answers

Hi. It makes no difference whether the plane is going straight up or at an angle. It's upward component is 100 meters per second regardless. Gravity will accelerate the packet at 1 g. The first part of it's fall will be upward, of course, until it reaches the apex of the trajectory. Total time of "flight" being 50 s gives you all the info you need. (Nope, not going to do the simple math for you. You wanted a physics answer, not arithmetic.)

2006-08-17 04:32:41 · answer #1 · answered by Cirric 7 · 1 0

You need to use s = ut + 1/2.at^2
s = distance (this will be the height of the airplane)
u = initial speed (this is 100m/S)
t = time (in this case 50 secs)
a = acceleration due to gravity

remember to make u negative because the initial speed is up but the final direction is down.

This ignores air resistance which is reasonable as you have no idea how large the package is, what it's shape is or it's mass.

2006-08-17 05:11:11 · answer #2 · answered by Stewart H 4 · 2 0

Wow, that is pretty simple arithmetic. How far does a plane going 100 m/sec go in 50 seconds?

But as for the final height, what is the terminal velocity of the object? Are we assuming a vacuum? It makes a difference when deciding from what height the object was dropped.

2006-08-17 04:38:06 · answer #3 · answered by Anonymous · 0 1

speed = 100m/s
time = 50s
so the height = distance if the object follows a straight path and fall vertically on the ground
then height = speed*time
since distance = speed * time
therefore height = 5000m
but since u have not mentioned whether the path the followed by the packet is straight line or a parabolic path,so i'm not sure.

2006-08-17 07:25:42 · answer #4 · answered by hellraiser 2 · 1 0

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2016-12-11 10:23:35 · answer #5 · answered by ? 4 · 0 0

Not sure, but at least 5000m if plane is going up vertically

2006-08-17 04:23:38 · answer #6 · answered by HeavenlyBull 2 · 1 0

I think you need the angle at which the airplane is rising.

2006-08-17 04:19:57 · answer #7 · answered by Jabberwock 5 · 0 1

There's not enough information to answer this question.

2006-08-17 04:17:15 · answer #8 · answered by mmenaquale 2 · 0 1

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