the object lies along the axis of a concave mirror with radius of carvature of 0.3 m, and the near end of the object lies 0.18 m from the mirror
2006-08-17 03:40:13 · 4 answers · asked by polly t 1 in Science & Mathematics ➔ Physics
First you need to find the distance to the object's image (s') by using the object's pre-image distance (s).
f = R/2
1/s + 1/s' = 1/f
magnification = -s'/s
Plug in and solve.
2006-08-17 03:50:39 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
f=1/r
2006-08-17 11:54:09 · answer #2 · answered by Vicky 1 · 0⤊ 0⤋
There is a direct formula for this question and is very simple, please refer to your text book. I would be able to help u, however, i have been on summer break for 4 months now and its been a while since i've reviewed my physics
2006-08-17 10:46:27 · answer #3 · answered by Ak2ng 3 · 0⤊ 0⤋
haan?????
2006-08-17 11:19:08 · answer #4 · answered by ani 2 · 0⤊ 0⤋