you can do this yourself. Just like decimal numbers have ones place, 10's place, 100's place, binary numbers have places too.
check it out...
decimal
10000, 1000, 100, 10, 1
binary
512, 256, 128, 64, 32, 16, 8, 4, 2, 1
Now you just need to figure out which combination of those numbers adds up to 762, but you can only use each number once.
Start with 512, You're going to need 512 to get to 762, because 512 is less than 762, so you put a 1 in the 512's place.
1, 256, 128, 64, 32, 16, 8, 4, 2, 1
Subtract 512 from 762, and you get 250. You won't need 256, so put a zero there.
10, 128, 64, 16, 8, 4, 2, 1.
You don't need to subtract anything. Keep going like this until all of the 762 is used up. You could use an online converter, but if this is for a class eventually you will have to do multiplication and division, and you'll want to know how to do it by hand otherwise you'll crash and burn on the exam.
122
101, 64, 32, 16, 8, 4, 2, 1
58
1011, 32, 16, 8, 4, 2, 1
26
10111, 16, 8, 4, 2, 1
'10'
101111, 8, 4, 2, 1
2
1011111, 4, 2, 1
1011111010
Double check your answer by adding up the place values of the 1's in your binary number.
2006-08-16 21:40:35
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answer #2
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answered by 006 6
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In order to convert a decimal number to a binary number you have to divide it to 2, and than divide the result by 2, and so on, till the result is 1, like this:
762 : 2 = 281, rest 0
281 : 2 = 140, rest 1
140 : 2 = 70, rest 0
70 : 2 = 35, rest 0
35 : 2 = 17, rest 1
17 : 2 = 8, rest 1
8 : 2 = 4, rest 0
4 : 2 = 2, rest 0
2 : 2 = 1, rest 0
The binary number that corresponds to your decimal number is the one you get if you right 1 followed by the rests you got, written from the last to the first:
1000110010
2006-08-16 21:59:22
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answer #3
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answered by Delfina 3
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