2006-08-16 20:12:02 · 7 answers · asked by jas 1 in Science & Mathematics ➔ Physics
Use ohms law. V=IR
If voltage is 12, and resistance is 6, then the current (I) is going to be 2 amps.
P=IV
So power = 12x2 = 24 watts
2006-08-16 20:16:23 · answer #1 · answered by sheograth06 2 · 0⤊ 0⤋
The power dissipated in a resistor is given by V^2/R. In this case V^2 = 144, R=6, 144/6 = 24 watts
2006-08-16 20:24:14 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
Current = Voltage / Resistant
= 12/6
= 2 Amp
Power = Current * Voltage.
= 2 * 12
= 24 Watts
Cheers.
2006-08-16 20:18:54 · answer #3 · answered by isz_rossi 3 · 0⤊ 0⤋
P=IV
But : V=IR so I=V/R
Therefore; I= 12/6
I= 2
Then: P=(2)(12)=24 watts
where: P=power (watts)
V=voltage (volts)
R=resistance(ohms)
I = current (amperes)
2006-08-16 20:57:14 · answer #4 · answered by cooler 2 · 0⤊ 0⤋
As we know, current flowing in that circuit is the ratio of V to R i.e. 2Amp, and power consumed is the product of I and V, power consumedin this case is 24 watt.
2006-08-16 21:16:03 · answer #5 · answered by yogen p 2 · 0⤊ 0⤋
this question is actual solved utilising here equations: V = IR the place V = voltage (V) I = contemporary (A) R = resistance (ohms) AND P = IV the place P = capability (W) Use the 1st equation to I, then the 2nd equation to discover P
2016-10-02 04:44:47 · answer #6 · answered by ? 4 · 0⤊ 0⤋
24Watts
2006-08-16 20:31:58 · answer #7 · answered by SAREK 3 · 0⤊ 0⤋