How can you prove. cos2x = cotx - sin2x / cotx?

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2006-08-16 19:24:22 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help

R.H.S=(cotx - sin2x)/cotx
=(cot x/cot x)-(sin 2x/cot x)
=1-((2sinx *cos x)/(cos x/sin x))
=1-(2 (sin x)^2)
=cos 2x=L.H.S
Hence proved

2006-08-16 19:35:46 · answer #1 · answered by kumar k 1 · 0⤊ 0⤋

R.H.S=(cotx - sin2x)/cotx
=(cot x/cot x)-(sin 2x/cot x)
=1-((2sinx *cos x)/(cos x/sin x))
=1-(2 (sin x)^2)
=cos 2x=L.H.S
Hence proved

2006-08-17 02:38:30 · answer #2 · answered by BrainCracker 4 · 0⤊ 0⤋

E=MC^2

2006-08-17 02:31:27 · answer #3 · answered by Paul G 5 · 0⤊ 0⤋