ok 7x -6=5/x +4 i got 50/35 or 1.4 but when i cheack it i get the wrong awnser....whats wrong?
2006-08-16 16:27:18 · 6 answers · asked by cyborg2389 1 in Education & Reference ➔ Homework Help
I'm not sure you have the equation written correctly.
If it is then multiply both sides by x and getting all to the left you have:
7x^2-10x-5=0
you have a quadratic equation ax^2+bx+c=0
whre the roots are x1= (-b+sqrt(b^2-4ac))2a
x1=(10+sqrt(100+140)/14
x2= (-b-sqrt(b^2-4ac))2a=
x2=(10-sqrt(100+140)/14
Just do the math and have fun.
2006-08-16 16:41:08 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
x=5
2006-08-17 00:44:06 · answer #2 · answered by ~Queen B~ 1 · 0⤊ 0⤋
First you need to cancel out the fraction, so multply 5/x on both sides. The 5/x will be canceled on the one side, leaving this:
7x - 6 (x/5) = 4
Then add the 6 on both sides to get the x's on one side and the numbers on another.
7x (x/5) = 10
Then solve the rest.
2006-08-16 23:36:59 · answer #3 · answered by Anonymous · 0⤊ 1⤋
ok, i don't have batteries in my graphics calculator, I got to
multiply both sides by X
7x^2-10x-5=0
When I plugged in your answer, I didnt get an equation either....
I have totally forgot how to solve what I came up with, but maybe its different than what you got. Perhaps you could school me on how to solve this...
2006-08-16 23:40:40 · answer #4 · answered by jennifer c 3 · 0⤊ 0⤋
7x - 6 = 5/x + 4
x(7x - 6) = 5 + 4
7xx - 6x = 9
x = 9
2006-08-17 01:05:05 · answer #5 · answered by C T H 2 · 0⤊ 1⤋
man that is a hard question. all i have to say is i tried man. imma be real i tried. maybe thats why i am in summer school
2006-08-16 23:45:08 · answer #6 · answered by Anonymous · 0⤊ 0⤋