(1) / (2x+3) + (1) / (x-1) = (1) / (2x+3)(x-1)?

0 ⤊

(1) / (2x+3) + (1) / (x-1) = (1) / (2x+3)(x-1)?

solve for x.

thank you.

2006-08-16 14:16:27 · 4 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics

4 answers

[x-1+2x+3]/[(x-1)*(2x+3)] = (1) / [(2x+3)(x-1)]
cancelling (1) / [(2x+3)(x-1)]

[x-1+2x+3] = 1

3x+2 =1

3x = (-1)

x = (-1/3)

2006-08-16 14:50:32 · answer #1 · answered by qwert 5 · 0⤊ 0⤋

x=-1/3

2006-08-16 14:22:19 · answer #2 · answered by R D 1 · 0⤊ 0⤋

Nope it's wrong.
Should be (x-1)+(2x+3)/ (2x+3)(x-1) then expand

2006-08-16 14:23:22 · answer #3 · answered by Burpz 2 · 0⤊ 1⤋

(1)/(2x+3)=(x-1)/((2x+3)(x-1)
(1)/(x-1)=(2x-3)/(2x+3)(x-1)
so: (1)/(2x+3)+(1)/(x-1)=((x-1)+(2x+3))/(2x+3)(x-1)
equal to: (3x+2)/(2x+3)(x-1)=(1)/(2x+3)(x-1)
then 3x+2=1
........3x=-1
..........x= -(1/3)

2006-08-16 14:32:54 · answer #4 · answered by uinchrist 2 · 0⤊ 0⤋