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What is....The square root of..... -9?

2006-08-16 13:59:06 · 10 answers · asked by udienowslave90 1 in Science & Mathematics Mathematics

10 answers

I know it. I know it, The answer is you need help on homework.

Right ?

2006-08-16 14:04:13 · answer #1 · answered by Anonymous · 0 2

3i in upper class in math
undefined in lower class in math
-9 doesnt have a root that is square in a teasing way

2006-08-16 21:13:17 · answer #2 · answered by Anonymous · 0 0

it's 3i
i stands for imaginary, which is -1
-1times3times3=-9
so root-9=±3i (there are always 2 answers for a square root.)
(i just learned it from grade 11 math, but i almost forgot trhough summer, it might be wrong)

2006-08-16 21:05:47 · answer #3 · answered by ☆LiAn☆ 3 · 0 0

Yep. It's 3i

2006-08-16 21:06:54 · answer #4 · answered by Papa John 6 · 0 0

the square of any negative number is imaginary . . .

it comes down to

rad -1 (x) rad 9

rad 9 = 3 or -3

si it's rad -1 (x) 3 or (x) -3

rad -1 =1i (or, i) so it's . . . +-3i

2006-08-16 21:50:42 · answer #5 · answered by Brian 3 · 0 0

You can not have a square root of a negative number.
The square of a number cannot be negative, you do not define the square root of a negative number.

2006-08-16 21:20:30 · answer #6 · answered by Mrs. H 6 · 0 1

Actually, the answer is plus-minus 3i ( +/- 3i) where i is imaginary.

that is both -3i and 3i are the correct answers.

2006-08-16 21:13:54 · answer #7 · answered by Neo_Apocalypse 3 · 2 0

3i ;p

2006-08-16 21:00:59 · answer #8 · answered by chdi1990 2 · 0 0

sqrt(-9) = sqrt(-1) * sqrt(9)
=i * +/- 3
= +/- 3i

2006-08-16 23:12:20 · answer #9 · answered by Anonymous · 0 0

3i where i is imaginary. duh

2006-08-16 21:03:53 · answer #10 · answered by Anonymous · 0 0

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