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2006-08-16 13:49:46 · 11 answers · asked by shih rips 6 in Science & Mathematics Mathematics

11 answers

The LCD in this equation is (x+2)

Multiplying the LCD to both sides, we got:

3x=-6-2(x+2)

Distribute -2 to (x+2), we got:

3x=-6-2x-4

Now, transfering

3x+2x=-6-4

5x=-10

divide both sides by 5

we got: x=-2

Checking:

3(-2)/(-2+2)=(-6)/(-2+2)-2

(-6)/0=(-6)/0-2

undefined=undefined-2

undefined=undefined

Note that in checking, there appeared a zero (0) denominator. Making a term undefined. However, the argument reamins valid because subtrating anything from undefined remains undefined. So don't wonder where the -2 in above solution went so that undefined=undefined

2006-08-16 14:03:59 · answer #1 · answered by Neo_Apocalypse 3 · 0 1

x = -2

2006-08-16 13:57:16 · answer #2 · answered by Cherstin and Adam F 3 · 0 1

3x/(x+2) = -6/(x+2) -2

Multiply both sides by (x+2) to get rid of the fractions

3x = -6 -2(x+2)

Multiply out the bracket

3x = -6 -2x -4

Tidy up

5x = -10

x=-2

2006-08-16 14:10:48 · answer #3 · answered by Anonymous · 0 1

x = -2
However, its one of those flawed questions as when you substitute x = -2 into the equation, you find that the denominator becomes 0! In which case, there is no solution if the questions is given in this form. If the question given is (3x) = (-6) - 2(x+2), then x=-2 would be legitimate.

2006-08-16 13:57:48 · answer #4 · answered by galford_sg 2 · 0 1

Value for x xould not be determined. Refer to your Algebra.

2006-08-16 15:15:39 · answer #5 · answered by ghondoruwo 1 · 0 1

x= -2 now go do your own homework.

2006-08-16 13:55:43 · answer #6 · answered by Anonymous · 0 1

x = - 2

You need to multiply everything by x + 2. You will then see what you need to do...I hope.

2006-08-16 13:56:20 · answer #7 · answered by rrrevils 6 · 0 1

ummmmmmmmmm 4! how would i possibly know that!

2006-08-16 13:54:57 · answer #8 · answered by bekka 3 · 0 0

no, you solve for x
btw there is no answer

2006-08-16 14:43:33 · answer #9 · answered by jester 2 · 0 1

do your own work

2006-08-16 13:54:57 · answer #10 · answered by Anonymous · 0 1

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