can you solve this math problem?

Question

(3x) / (x+2) = (-6) / (x+2) - 2

solve for x.

Answer 1

[(3x) / (x+2)] = [(-6) / (x+2)] - 2

Multiply through by "x + 2"

(x + 2)*[(3x) / (x+2)] = (x + 2)*[(-6) / (x+2)] - 2*(x+ 2)

(3x) * (x + 2) / (x + 2) = [(-6) * (x + 2) / (x+2)] - (2x+ 4)
3x = -6 - 2x - 4
5x = -10
x = -2

Plug x = -2 into the original equation to check for extraneous solutions.
[(3x) / (-2+2)] = [(-6) / (-2+2)] - 2
(3x / 0) = (-6 / 0) - 2
Since you cannot have zero in the denominator, x= - 2 is NOT a solution.
No solution.

Answer 2

The LCD in this equation is (x+2)

Multiplying the LCD to both sides, we got:

3x=-6-2(x+2)

Distribute -2 to (x+2), we got:

3x=-6-2x-4

Now, transfering

3x+2x=-6-4

5x=-10

divide both sides by 5

we got: x=-2

Checking:

3(-2)/(-2+2)=(-6)/(-2+2)-2

(-6)/0=(-6)/0-2

undefined=undefined-2

undefined=undefined

Note that in checking, there appeared a zero (0) denominator. Making a term undefined. However, the argument reamins valid because subtrating anything from undefined remains undefined. So don't wonder where the -2 in above solution went so that undefined=undefined

Answer 3

3x/(x+2)=(-6-2(x+2))/(x+2) taking LCD
=>3x=-6-2x-4 removing the brackets
=>5x=-10 transposing
x=-2

Answer 4

Solve,

(3x) / (x + 2) = (-6) / (x + 2) - 2

(3x) / (x+2) + (6)/(x + 2) = 2

(3x + 6) / (x + 2) = 2

3x + 6 = 2(x + 2)

3x - 2x = -6 + 4

x = -2

Answer 5

times both sides by the denominators and simplify the fractions

Answer 6

haha no lol goodluck with that :)

Answer 7

ideaquest has right answer.