If the population of a city was 102,002 in the 2000 census and increases by a factor of 1.001 each year, what?

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If the population of a city was 102,002 in the 2000 census and increases by a factor of 1.001 each year, what?

would be the population in 2009?

2006-08-16 13:10:22 · 4 answers · asked by It's me Snitches 2 in Science & Mathematics ➔ Mathematics

4 answers

Get your calculator out - I'm pretty sure the way to do this is:
102,002 times 1.001 to the power 9. Or (102,002 * 1.001 * 1.001 * 1.001 * 1.001 * 1.001 * 1.001 * 1.001 * 1.001 * 1.001)

I don't have one with me so cant check, sorry :)

2006-08-16 13:20:31 · answer #1 · answered by Anonymous · 1⤊ 0⤋

I'm assuming you mean that the population increases by 0.1% every year.

It would be 102,924 in 2009.

2006-08-16 20:17:04 · answer #2 · answered by TheOnlyBeldin 7 · 1⤊ 0⤋

That should be
102924

2006-08-16 20:24:09 · answer #3 · answered by the oracle 1 · 0⤊ 0⤋

102923.66

2006-08-16 20:15:23 · answer #4 · answered by Heatmizer 5 · 1⤊ 0⤋