your question is:
3X² - 4X - 5 = 0
Using Quadratic formula, u can easiy solve it
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If we have a form aX² + bX + C = 0
then X = [-b ± √(b²-4ac)]/2a
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for your equation, a =3 , b=-4 and c=-5
by putting these values in quadratic foruma we get.
X = [-b ± √(b²-4ac)] / 2 a
X = [-(-4) ± √(-4² -4(3)(-5))] / 2(3)
X = [+4 ± √( 16+60)] / 6
X= [+4 ± √76]/6
so X=(4+√76/6 and X = (4-√76)/6 >=====Answers
Or
X= (2.1196) and X =(-0.78629) <=====Answers
2006-08-16 13:00:51
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answer #1
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answered by Da Sahar SToRaY 2
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Divide each term via 3. x²-4/3x-5/3=0 x²-4/3x=5/3 x²-4/3x+sixteen/36=5/3+sixteen/36 (x-4/6)²=60/36+sixteen/36 (x-4/6)²=seventy six/36 ?((x-4/6)²) = ?(seventy six/36) x-4/6=?seventy six/6 x-4/6=2?19/6 x=(4±2?19)/6 x=(2±?19)/3
2016-12-11 10:03:41
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answer #2
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answered by ? 4
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I don't think it can be solved... Because that's a trinomial.. and in order to facor it you need something that multiplies to be 15 (because of the 5 on the end and the 3 in front of the x2) and has a difference of 4... I can't think of any real numbers that can do that... I'm sorry I'm not much help.
2006-08-16 12:44:41
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answer #3
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answered by Anonymous
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Use the quadratic formula. Type quadratic into a search field and you will be taken to specific help. Then plug in the above equation to find your answer.
2006-08-16 12:43:23
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answer #4
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answered by Falcon Boy Toy 3
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using the quadratic formula it is (4+the square root of 76)/6 or
(4-the square root of 76)/6
x=2.12 or -0.79
2006-08-16 13:30:40
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answer #5
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answered by Anonymous
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Sure. Like Falcon said, use the quadratic formula. You should get:
x=(sqrt(19)+2)/3 or x = -(sqrt(19)-2)/3
edit:jomer, your factorization isn't even close. expand it. this doesn't factor cleanly.
2006-08-16 12:45:15
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answer #6
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answered by a_liberal_economist 3
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Sorry I didn't factor correctly and yeah a_liberal is right !
2006-08-16 12:44:45
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answer #7
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answered by iJomer 4
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