Math question?

Question

How would you solve 3q/r - 5/p
p=-4, q=8, r=-10
Thanks

How would you solve 3q/r - 5/p
p=-4, q=8, r=-10
If I plug it in:
3(8)/-10 - 5/-4
Then I would have
24/-10 - 5/-4
I am not real sure what to do with the negatives. Please ....serious answers only.

Answer 1

*Replace each letter with the given value

3(8)/-10 - 5/(-4)=

24/-10 - 5/-4=

-2.4 - -1.25=

-2.4+1.25=

-1.15

Are you sure that's the problem? If it is, then there's your answer......

Answer 2

3 X 8 divided by 10 - 5 divided by -4

Answer 3

replace the letters with the numbers then you would have

3(8)/10-5/-4

multipy the 3 and 8 =24
divide 24 by 10=2.4
divide 5 by -4=-1.25
-2.4--1.25=-1.15 (the two neg cancel each other out)

Answer 4

solve 3q/r - 5/p
p=-4, q=8, r=-10 so

3(8/-10) - 5/-4 =

Answer 5

I hope this isn't a trick question, but it looks like you are being INCREDIBLY lazy about this one. Just replace the letters with the numbers (like a color with numbers book you may have used when you were little) and solve. It's bad enough you can't even lift your finger to type it into a calculator. Good gawd, girl. Get off your butt and do what little work this "problem" requires to get the correct answer.

Answer 6

replace the letters in the actual problem with the ones of equal value in the key

Answer 7

3(8)/-10 - 5/-4
24/-10 - 5 /-4
-2.4 - - 1.25
-1.15

Answer 8

3(8)/-10 - 5/(-4)
=-2.4 +1.25
=-1.15

Answer 9

Plug in the variables, the use the PEMDAS method.

Answer 10

bedmas

3(8)/(-10) - 5/(-4)
3(-.8) - (-1.25)
-2.4 - (-1.25)
= -1.15