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2006-08-16 11:47:32 · 19 answers · asked by pinkpockadotz333 2 in Science & Mathematics Mathematics

19 answers

no

2006-08-16 11:52:06 · answer #1 · answered by Piano_Man 2 · 0 1

No... i wrote a program to check if 323 = 0 mod p for primes less than the square root


EDU» mod(323, primes(floor (sqrt(323))))

ans =

1 2 3 1 4 11 0

EDU» primes(floor(sqrt(323)))

ans =

2 3 5 7 11 13 17

We can see that 17 | 323

And in fact 323 = 17 * 19

2006-08-16 18:56:32 · answer #2 · answered by Anonymous · 0 0

No, 323=19*17

2006-08-16 18:54:17 · answer #3 · answered by James B 1 · 0 0

No. 17 * 19 = 323

2006-08-16 20:06:54 · answer #4 · answered by CSUFGrad2006 5 · 0 0

No

http://primes.utm.edu/lists/small/1000.txt

2006-08-16 18:54:33 · answer #5 · answered by a_liberal_economist 3 · 0 0

NO...
323 is divisible by 17 and 19...

2006-08-16 23:15:39 · answer #6 · answered by Anonymous · 0 0

No.

It divides evenly by 17 and 19.

17 x 19 = 323

2006-08-16 18:53:18 · answer #7 · answered by p_rutherford2003 5 · 1 0

no, 323 is not a prime #

2006-08-16 18:58:46 · answer #8 · answered by Shirley S 1 · 0 0

No, it has 2 factors, 17 and 19.

2006-08-16 18:58:28 · answer #9 · answered by STILL standing 5 · 0 0

No, because it can divided by 17 and 19.

2006-08-16 18:58:27 · answer #10 · answered by sonicwingmode 2 · 0 0

no it can be divied.
any numbers that can be divied more than 1 isnt a prime .
prime numbers is when u can divide it with the number its self and the number 1

2006-08-17 10:42:16 · answer #11 · answered by Anonymous · 0 0

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