no
2006-08-16 11:52:06
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answer #1
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answered by Piano_Man 2
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No... i wrote a program to check if 323 = 0 mod p for primes less than the square root
EDU» mod(323, primes(floor (sqrt(323))))
ans =
1 2 3 1 4 11 0
EDU» primes(floor(sqrt(323)))
ans =
2 3 5 7 11 13 17
We can see that 17 | 323
And in fact 323 = 17 * 19
2006-08-16 18:56:32
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answer #2
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answered by Anonymous
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No, 323=19*17
2006-08-16 18:54:17
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answer #3
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answered by James B 1
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No. 17 * 19 = 323
2006-08-16 20:06:54
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answer #4
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answered by CSUFGrad2006 5
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No
http://primes.utm.edu/lists/small/1000.txt
2006-08-16 18:54:33
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answer #5
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answered by a_liberal_economist 3
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NO...
323 is divisible by 17 and 19...
2006-08-16 23:15:39
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answer #6
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answered by Anonymous
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No.
It divides evenly by 17 and 19.
17 x 19 = 323
2006-08-16 18:53:18
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answer #7
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answered by p_rutherford2003 5
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no, 323 is not a prime #
2006-08-16 18:58:46
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answer #8
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answered by Shirley S 1
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No, it has 2 factors, 17 and 19.
2006-08-16 18:58:28
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answer #9
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answered by STILL standing 5
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No, because it can divided by 17 and 19.
2006-08-16 18:58:27
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answer #10
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answered by sonicwingmode 2
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no it can be divied.
any numbers that can be divied more than 1 isnt a prime .
prime numbers is when u can divide it with the number its self and the number 1
2006-08-17 10:42:16
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answer #11
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answered by Anonymous
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