A.) An Extreme Rules Match with Tommy Dreamer & Sandman.
B.) A Hell in a Cell match with the Undertaker.
C.) A Street Fight with John Cena.
D.) A Kiss My A** match with Mr. McMahon.
2006-08-16 10:37:34 · 11 answers · asked by Anonymous in Sports ➔ Wrestling
D, definitely. I would love to watch Heyman kiss McMahon's backside, lol!
2006-08-16 11:10:31 · answer #1 · answered by The Nana of Nana's 7 · 0⤊ 0⤋
know wrestling they would drag it out so all of them but in a different order
Raw would be "street fight with cena" the tuesday they would drag his asss up and put him in "An extreme rules match" let him recover from that then Raw "undertaker" then after the match make him kiss my asss.
or
Tell him about the match on RAW about extreme rules on ECW but Big show would help him out then next Raw Street fight with john cena but Edge would help him then a match between big show with edge vs john cena and who ever he picks while Paul would fight the undertaker and then kiss his asss
2006-08-16 17:44:33 · answer #2 · answered by Dum Spiro Spero 5 · 0⤊ 0⤋
D.) A Kiss My A** match with Mr. McMahon. CUSE IT WOLD MACK A FUDE WITH WWE AND ECW AND I WOLD LIKE THAT
2006-08-16 20:47:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋
He could be in any of these matches! They all seem entertaining enough, Heyman probably deserves it!!
2006-08-16 17:42:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
none of the above he would be in a lingerie match with big show because he cares about him so much
2006-08-16 21:11:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋
a,b,d i wanna c him do all of those cenas a fighter not awrestler sooo heyman could beat him :)
2006-08-16 17:44:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋
hell in a cell i think that undertaker would kick his ***
2006-08-16 17:57:49 · answer #7 · answered by Michael A 2 · 0⤊ 0⤋
D. Oh Yeah..
2006-08-16 17:44:58 · answer #8 · answered by Jaunt 1 · 0⤊ 0⤋
B
2006-08-16 18:34:07 · answer #9 · answered by UAI 3 · 0⤊ 0⤋
A THAT WOULD BE AWSOME
2006-08-16 18:31:32 · answer #10 · answered by ? 2 · 0⤊ 0⤋