I need help with a word problem. In a barn yard were 18 pigs and chickens. If there were 56 legs in all, how?

Question

Please show me how to work this out. I think I am so dumb I can't figure this one out.

Answer 1

10 pigs + 10 x 4 = 40 legs
8 chickens: 2 x 8 = 16 legs

Total of 56 legs

Answer 2

Let's say the number of pigs is represented by the letter p, and the number of chickens is the letter c. Then
p + c = 18
(total number of pigs + total number of chickens = total number of animals)

Now for every pig, there are 4 legs, so there are
4 x p pigs legs
In the same way, there are
2 x c chickens legs

This gives a total of
(4 x p) + (2 x c) = 56 legs in total (from the question)

If we rewrite p + c = 18 as
c = 18 - p
we can put this value for c into the leg equation. This gives
4p + (2 x (18 - p)) = 56
simplifying this...
4p + 36 - 2p = 56
4p - 2p = 56 - 36
2p = 20
p = 10
So there are 10 pigs.
c = 18 - p
c = 8
And there are 8 chickens

The End

Answer 3

Pigs are x's with 4 legs and chickens are y's with two legs. Therefore: x + y = 18 animals and 4x + 2y = 56 legs. Rearrange these and you have
x=18 - y [subtract y from both sides of the equation for animals]

4(18-y) + 2y =56 [sub new x into equation for legs]
72 - 4y +2y = 56 [solve the brackets first]
72 - 2y = 56 [combine the y's]
72-56 = 2y
16 = 2 y
y = 8 (chickens)

x + y = 18
x= 18 - y
x = 10 (pigs)

Just remember that if you do something on one side of the equation you must do it on the other as well.

Answer 4

There is 10 pigs & 8 chickens. Pigs have 4 feet: 4 X10= 40 plus 8 chickens w/ 2 feet: 2 X 8= 16; therefore, 16 + 40 = 56 legs.

Answer 5

You know that pigs have 4 legs and chickens have 2 legs.
Let's say X is the number of pigs and Y is the number of chickens.

From your statement you know X + Y = 18.
You also know 4X + 2Y = 56, since each pig has 4 legs and each chicken two.
So you have two equations now. You have to solve for one of the variables and plug that back into the other equation.

Let's use the simpler one and solve for Y.
X + Y = 18 (subtract Y from either side)
X = 18 - Y.

Putting this back into the other equation you get
4(18 - Y) + 2Y = 56
72 - 4Y +2Y = 56
72 - 2Y = 56
16 - 2Y = 0
so Y = 8

Since X + Y = 18, X = 10.
Checking (4*10) + (2*8) = 56, we're done!

Answer 6

There are 10 pigs=40 legs and then 8 chickens=16
40+16=56

Answer 7

10 pigs and 8 chickens

Each pig has 4 legs and each chicken has two. You can use a guess and check method to solve it, starting with 7 pigs and 7 chickens, then changing the number until you have the right amount of total legs.

Answer 8

in case you do no longer comprehend algebra (or notwithstanding in case you do) you may make a tribulation/errors table. All I did became into try some a threat mixtures till I have been given a a threat one. C = chickens H = hogs Multiply with the aid of the form of legs of each and every to get the whole sort of legs: C(x2) H(x4) Legs a million       a million       6   (no longer adequate) 3       3       18  (no longer adequate) 5       5       30  (no longer adequate) 7       7       40 two  (no longer adequate) 7       9       50   (no longer adequate) (notice: I observed that I only needed 6 extra here, so I further certainly one of each and every animal): 8       10       fifty six   yet we desire 22 animals.... sixteen chickens 6 hogs I further 2 chickens and took away a million hog till the sum became into 22. (2 chickens = a similar sort of hog legs)

Answer 9

11 pigs have 44 legs
7 chickens have 14 legs
18 pigs and chickens and 58 legs

Answer 10

there are several solutions. there could be 14 pigs at 4 legs each=56 total. considering chickens have 2 legs there are several solutions....you could have 13 pigs (52 legs) + 2 chickens (4 legs).....OR 12 pigs (48 legs) + 4 chickens (8 legs) and so on.....