solve z^3 = -i8?

2 ⤊

just to solve the complex number formula, must be so simple i just cant see it!!

z = -i8^1/3
z = -i^1/3* 2
z = -2i

2006-08-16 09:16:33 · answer #1 · answered by John J 6 · 1⤊ 1⤋

2006-08-16 16:38:10 · answer #2 · answered by Anonymous · 0⤊ 1⤋

z^3 = -i8?

z^3 = -8i
z^3 = 8*i^3 -----> (i^3 = -i)
z^3 = [(2)^3]*(i^3)
z = 2i

2006-08-16 16:14:25 · answer #3 · answered by wheezer_april_4th_1966 7 · 1⤊ 2⤋

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2006-08-16 16:14:51 · answer #4 · answered by digital genius 6 · 0⤊ 2⤋