2006-08-16 07:22:20 · 14 answers · asked by john erick 1 in Science & Mathematics ➔ Mathematics
Solving for celsius
F = 9/5 C + 32
- 32 -32
subtracting - 32 from both sides
F - 32 = 9/5c
5/9 F -32 = 5/9(9/5)C
Invert 9/5 to 5/9 multiply to both sides
5/9F - 32 = C
The answer is 5/9F-32 = C
2006-08-16 07:52:22 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
F=9/5C+ 32,solve for C.
F-32=9/5C
5C = 9/ (F-32)
C = 9/ {5(F-32)}.
2006-08-16 07:31:19 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋
F = 9/5C + 32
F - 32 = 9/5C
(F - 32)/9 = 1/5C
(F - 32)5/9 = 1/1C
(F - 32)5/9 = C
C = (F - 32)5/9
C = (5/9)(F - 32)
2006-08-16 07:41:20 · answer #3 · answered by Brenmore 5 · 0⤊ 0⤋
F = 9/5 C + 32 -----> 9/5 C = 32 - F
C = 80 - 5/9F
2006-08-19 17:15:17 · answer #4 · answered by Smartie 3 · 0⤊ 0⤋
That is the equation for the conversion fron Celcius to Fahrenheit temperature scales...
Solve for C...
F = 9/5C + 32
9/5C = F - 32
C = 5F/9 - 160/9 = 5F/9 - 17.78
2006-08-16 07:30:01 · answer #5 · answered by AresIV 4 · 0⤊ 0⤋
Sure:
Subtract 32 from both sides of the equation.
then divide both sides of the equation by 9/5
and your answer will be an expression of
C = 5 / 9 (F - 32)
2006-08-20 01:43:58 · answer #6 · answered by zahbudar 6 · 0⤊ 0⤋
C=(5/9)*(F-32) will solve for C. You will need F "Fahrenheit" value to complete the equation
2006-08-16 07:29:21 · answer #7 · answered by R R 3 · 0⤊ 1⤋
I do it a diffrent way since 9/5 = 1.8
C * 1.8 + 32 = F
100 * 1.8 + 32 = 212
2006-08-16 07:38:05 · answer #8 · answered by Kevin H 7 · 0⤊ 0⤋
C=(5F-160)/9
2006-08-16 07:29:30 · answer #9 · answered by me 3 · 0⤊ 0⤋
This is basic algebra.
Here's a hint: Start by subtracting 32 from both sides of the equation.
2006-08-16 07:27:42 · answer #10 · answered by Brian L 7 · 1⤊ 0⤋