Use a graphing calculator.
2006-08-16 07:23:07
·
answer #1
·
answered by Anonymous
·
0⤊
2⤋
a) There can only be 3 zeroes (same as roots) by the fundamental theorem of algebra because f is of degree 3.
b) The first and second derivative tell us that there are three points of inflexion, two of which are extreme points.
c) Sorry, have no idea what "end behavior" means - it must be some American term.
d)
2x^3-9x^2-24x+31= (x-1)(2x^2-7x-31)
2x^3-9x^2-24x+31= (x-1)(x-6.0575)(x+2.5575)
So zeroes are at x=1, x=6.0575 and x= -2.5575
e) f'(x) = 6x^2-18x-24
To find coords of extrema, we set f'(x)=0, so then we have:
6x^2-18x-24=0
x^2-3x-4=0
(x+1)(x-4)=0
Thus extrema are at x=-1 and x=4.
You can calculate f(-1) and f(4) yourself. If my arithmetic is correct, f(4) = -81 and f(-1)=44.
f) The graph rises on (-infinity,-1] and [4,infinity)
the graph falls on (-1,4).
2006-08-16 07:59:44
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
a)possible real roots number three as the degree of the polynomial is three and the rule is as many roots as is the degree of the polynomial
b)possible extreme points=2
c)as x increases to infinity f(x) also increases to infinity
d)2x^3-9x^2-24x+31
f(1)=2-9-24+31=0
therefore x-1 is a factor
synthetically dividing by x-1
2 -9 -24 31
0 2 -7 -31
2 -7 -31 0
so the quotient on division
=2x^2-7x-31
roots=[7+/-(49+248)^1/2]/4
the real zeros are 1,[7+/-(297)^1/2]/4
e)f'(x)=6x^2-18x-24=0 =>x^2-3x-4=0 =>(x-4)(x+1)=0 so the extrema are at x=4 and x=-1
minimum at 4 and maximum at -1,the minimum and the maximum values being -81 and 45
f)graphing the curve will help us to seethe rising and falling behaviour of the curve.
however from minus infinity to -1 it rises and at -1 it changes direction.from -1 to 4 it falls.it changes direction once again at 4 and rises.at -1 it is concave downwards ( a local maximum) and at 4 it is concave upwards ( a local minimum)
2006-08-16 07:57:04
·
answer #3
·
answered by raj 7
·
0⤊
0⤋
a) 3 possible because largest power in function = x^3
b) 2 = 3-1 because largest power in function = x^3
c) as x --> infinity f(x) ---> infinity
d) solve 0 = 2x^3 - 9x^2 - 24x +31
e) solve 0 = 6x^2 - 18x - 24 (derivitive)
f) make a picture
2006-08-16 07:27:48
·
answer #4
·
answered by Grant d 4
·
1⤊
0⤋
I would, but I only have a couple of minutes. Just get the derivative and factor it out and you'll be on your way.
2006-08-16 07:24:51
·
answer #5
·
answered by Ox Cimarron 2
·
0⤊
1⤋
identify the g) question on your homework you should really do on you own.
2006-08-20 03:58:40
·
answer #6
·
answered by chris m 5
·
0⤊
0⤋
ooh wow beginning calculus. i bet once you learn the rest, you'll be asking much more difficult questions
2006-08-16 07:29:50
·
answer #7
·
answered by Daniel C 4
·
0⤊
1⤋
When in class .... pay attention...when on yahoo answers.. don't try to get your homework done..
2006-08-16 07:27:49
·
answer #8
·
answered by honey 3
·
0⤊
1⤋
hehe! i'll applaud u for trying to get ur homework done for u!
2006-08-16 07:26:26
·
answer #9
·
answered by falcone99 1
·
0⤊
2⤋
have no clue.... LOL... should try paying attention in school and you would not have to ask for help...
2006-08-16 07:26:13
·
answer #10
·
answered by sexy momma 3
·
0⤊
2⤋