if y-2 = 1/2(x-3)
then 2*(y-2) = 2* 1/2(x-3)
this equals
2y-4 = x-3
so 2y-4 +3 = x-3 +3
or x=2y-1
2006-08-16 06:59:48
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answer #1
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answered by PC Doctor 5
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first of all, this is an equation in two unknowns which will require two equations to solve completely.
Given only one equation, we can only come up with an expression for the value of the variable x.
So:
y - 2 = 1/2 ( x - 3 ) now multiply both sides by 2
2y - 4 = x - 3 now add 3 to both sides
2y -1 = x Answer
2006-08-20 08:39:30
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answer #2
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answered by zahbudar 6
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There is not a single answer, as the y is still unknown. However, you can change the way the equation reads if you rewrite it as follows:
x=2y-1
2006-08-16 14:00:29
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answer #3
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answered by ; - } 5
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You need two equations to solve for two variables, X could be anything if you make it fit with Y.
2006-08-16 13:57:44
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answer #4
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answered by Anonymous
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1 short of twice of y
2006-08-16 13:57:09
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answer #5
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answered by honey 3
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That depends on what you use for y.
x can be variable that you want, as long as the y value matches accordingly.
2006-08-16 13:57:31
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answer #6
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answered by mthtchr05 5
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y-2=(x-3)(1/2)
(2)(y-2)=x-3
(2)(y-2)+3=x
Reduced further . . .
2y-4+3=x
2y-1=x (this is the answer)
2006-08-16 14:11:49
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answer #7
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answered by DClegalaide 2
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x=2y-1
2006-08-20 13:50:05
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answer #8
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answered by Anonymous
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x=2y-1 right?
2006-08-16 13:58:42
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answer #9
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answered by petvet32190 1
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