Trig final problem please help?

Question

I just got my trig final back can anyone show ,me how to work this one?
The wheels of a truck are making 360 rpm as the truck travels at 60mi/h. Find the diameter of the wheels in inches.

Answer 1

360 rev/min * 60 min/hr * pi * d in / rev * = 60 mi/hr * 63360 in/mi

d = 60 * 63360 / (360 * 60 * pi) in
d ~= 56 inches.

Answer 2

First you need to get all the units to be the same. So the truck is traveling 1 mile/minute, so the circumference of the wheel is 1/360 miles, the diameter would be 1/360/pi miles. Convert miles to inches 5280*12/360/pi = 56.0 inches.

A biggggg tire.

Answer 3

60 mph is one mile per minute. One mile is 5280 feet. In one minute, the wheels turn 360 times. Multiply 5280 feet by 12 inches per foot, then divide by 360 to get 176 inches. That's the circumference of the wheel.

The circumference equals pi d, so the diameter is 56 inches.

Answer 4

I sure hope this isn't for a final you are taking now. I answer based on my trust in a total stranger:

First, you don't want mph. The hour has to go to minutes, and the miles will be too big to calculate a radius of a tire with, so convert mph to inches per minute.

60 mph = 63360 inches per minute.

In one minute, you make 360 revolutions, so dividing you get 176 inches per revolution, which is circumference.

I'm sure you can figure it out from there. You know the circumference, so what's the radius, or diameter?

Answer 5

OK
60 mi/hr*5280*12/3600 = 1056 inches/second for the trucks speed.

360/60 = 6 rps for the wheels

So 6*circumference = 1056 inches and
circumference = 176 = πD so D = 56 inches.

Not much trig, just horse sense


Doug

Answer 6

There is very little trig in this problem, only a lot of conversion to similar units before use of the circle perimeter formula.

First of all, the question asks for an answer in inches. So we will need to convert the miles statement into inches.

Secondly, the speed of tire rotation is given in "per minute" quantity, while the vehicle speed is given in "per hour" units.
so these need to be converted to "like" units before computation can begin. So, 60 miles per hour divided by 60 (there are 60 minutes in one hour) = 1 mile per minute.

Now convert the unit "Mile" into "Inches"...

1 x 5,280 (feet per mile) x 12 (inches per foot) = 63,360
inches traveled in one minute.

The tire went around 360 times to create a path 63,360 inches long. So, to find out how far it is around the tire itself...

63,360 divided by 360 = 176.

So the distance around the tire (circumference) is 176 inches.

The question asks for the diameter of the tire.

Circumference = Pi x Diameter

So: 176 inches = 3.1416 x diameter in inches

or 176 / 3.1416 = 56.022 inches
Answer: about 56 inches in diameter

Answer 7

60 mi /h
means 60 mi /60 min or 1mi per minute
let the diameter be D
then perimeter of tyre is pi*2*radius=pi*D
so 360 rpm means
360 rotations in one minute or 360 *pi*D distance travelled
in one minute

as in one rotation pi*D (perimeter) is the distanmce travelled
360 * pi * D =1 mi=5280*12 inches

D=(5280*12) /(360*pi) inches
D= 56 inches approx. (pi=3.1415926535...)

Hope it helps

Answer 8

csc X = a million/sin X sec X = a million/cos X cot X = cos X/sin X tan X = sin X/cos X I blanketed all 4 for thoroughness. it is continually more effective common to deal merely with cosines and sines, so that you replace your equation to easily comprise those. (3/sin X) / ( 5/sinX - 6 cos^2 X/sin^2 X ) you desire a immediately ahead denominator for the fractions in the deonominator, so: (3/sinX) / (5 sin X/sin^2 X - 6 cos^2 X/sin^2 X (3/sin X) / [ (5 sin X - 6 cos^2 X)/sin^2 X ] A sin X cancels out of both the numerator and denominator, leaving you with: 3 / [ (5 sin X - cos^2 X)/sin X ] The sin X might want to correctly be moved to the numerator: 3 sin X / [ 5 sin X - cos^2 X ] cos^2 X = a million - sin^2 X , so: 3 sin X/ [5 sin X - a million + sin^2 X] which might want to be rearranged to: 3 sin X / [ sin^2 X + 5 sin X - a million] Edit: i did not seize your squared element.

Answer 9

36''