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BaCl2 +CuSO4 (both in solution) = BaCl2 (solid, unsoluble) + CuCl2 (in solution)
(or Ba^2+ + 2Cl^- = BaCl2)
CuSO4 (solution) + Fe (metal) = Cu(metal) + FeSO4 (solution)
(or Cu^2+ + Fe = Cu + Fe^2+)

2006-08-16 02:04:25 · answer #1 · answered by hi 2 · 0 1

it extremely is an equation showing a displacement reaction. Fe, being greater reactive than Cu, will displace the less reactive steel from its aqueous answer. this could be a displacement rule. whilst this reaction happens, the blue CuSO4 would be develop into diminished green FeSO4 and there will be a reddish brown Cu coating on the forged Fe. i'm hoping this help you to understand the reaction. =]]

2016-12-17 11:45:51 · answer #2 · answered by ? 4 · 0 0

BaCl2 + CuSO4 --- BaSO4 +CuCl2

CuSO4 +Fe --- Cu + FeSO4

2006-08-16 02:02:43 · answer #3 · answered by !_! 2 · 1 0

1)BaCl2 + CuSO4 ---->BaSO4+ CuCl2
2)CuSO4 + Fe-------->FeSO4+Cu

2006-08-16 02:12:24 · answer #4 · answered by star123 2 · 0 0

That is just an expression. No = where got equation?
But if you mean the result then we will get
Ba(SO4)+CuCl2
FeSO4 + Cu

2006-08-16 01:52:45 · answer #5 · answered by ET 3 · 0 0

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