2006-08-15 22:17:57 · 16 answers · asked by Scotty Sunday 3 in Science & Mathematics ➔ Mathematics
1953 and you would have made a point if you would have said feb 29 th
2006-08-15 22:21:30 · answer #1 · answered by adriana 3 · 0⤊ 0⤋
1952 or 1953, depending on your birthday. The question suggests, but does not definitively state, that the birthday is Feb. 28. If you were born Dec. 1, 1952, you would still be 53 on 2/28/06.
2006-08-16 05:27:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2006 - 53 = 1953
2006-08-16 07:15:20 · answer #3 · answered by Sandy 2 · 0⤊ 0⤋
This needs complex mathematics to solve. Complex? Yeah, like imaginary numbers. Imaginary? Yeah, like eleventy, or sixtytwelve..
Here is how to work it out:
Feb 28 2006
= 02 28 2006
reverse the first two digits 02 becomes 20.
This is called an inverse. Invert again by subtracting one (you can write 20^-1). Eat the carrot and you get 19. This is the first part of our answer.
Next add the two parts of 2006. 20+06 = 26. Add 28 to that, which gives, 28 and 26 = 54. (%+4 =9) so add 54+9 = 63.
Since you are working in the decimal system, to transfer to the complex plane, eliminate decimal part 63 - 10 = 53
This is the second part of the answer
Answer = first part & second part
= 19 & 53
=1953
Its simple really when you have such genius.
2006-08-16 07:07:38 · answer #4 · answered by blind_chameleon 5 · 0⤊ 0⤋
19 53
2006-08-16 05:22:05 · answer #5 · answered by Mim 7 · 0⤊ 0⤋
1953
2006-08-16 05:42:52 · answer #6 · answered by Keyman 3 · 0⤊ 0⤋
1953
2006-08-16 05:28:02 · answer #7 · answered by Guppy 2 · 0⤊ 0⤋
1953
2006-08-16 05:22:01 · answer #8 · answered by stop_lyin 2 · 0⤊ 0⤋
1953
2006-08-16 05:21:17 · answer #9 · answered by grahamma 6 · 0⤊ 0⤋
1953
2006-08-16 05:20:36 · answer #10 · answered by ? 5 · 1⤊ 0⤋
1953
2006-08-16 05:20:06 · answer #11 · answered by Some Guy 6 · 1⤊ 0⤋