A man spend 1/3 of his money and lost 2/3 of the remainder.
He was let with 12 dollars.
How much did he start with?
Please if you find the answer please explain me how did you get it. Thank you!!!
2006-08-15 18:30:47 · 18 answers · asked by Angel 1 in Education & Reference ➔ Homework Help
He started with x dollars.
x - (1/3)x - (2/3)[x - (1/3)x] = 12
(2/3)x - (2/3)x + (2/9)x = 12
x = 12(9/2) = 54
He started with $54, lost $18, leaving $36, then lost $24, leaving him with $12.
2006-08-15 18:39:38 · answer #1 · answered by bpiguy 7 · 1⤊ 0⤋
Work backwards:
12 is 1/3 of what he had before spending 1/3, which would be 36.
So, after spending 1/3, he was left with $36.
That means $36 is 2/3 of what he started with.
Therefore, he started with 36 / 2 X 3 = $54
2006-08-15 18:45:15 · answer #2 · answered by vinny_the_hack 5 · 0⤊ 0⤋
Let x = total dollars
If he spent 1/3 of x, he was left with (2/3)x and if he lost 2/3 of the remainder he was left with (1/3)*(2/3)x or (2/9)x = 12. Now divide both sides by 2/9 (invert and multiply)
x = $12 * (9/2)
x = $54
He spent 1/3 of $54 which equals $18 leaving him with $36. He lost 2/3 of that (or $24) leaving him with $12.
2006-08-15 19:00:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
To represent a number by fractions, you're taking away from a whole number. A whole number represented by a fraction would be like 4/4, or 1/1, or whatever. Anyway, you take 12 and make it fraction (12/1), then you flip it (1/12), because you have to do that so you multiply it by 1/3. However, the way I do it is...1/3 is one part of 3/3, so I just take 12, which would be the 1/3, and multiply it by 3.
2006-08-15 18:45:19 · answer #4 · answered by socomgoat 2 · 0⤊ 0⤋
money = 1/3 spent + (1/3 left + 2/3 lost)
money = 1/3 spent + (12 left + 24 lost) { i got the 24 by multiplying the 12 by 2 as he lost twice what he kept - lost 2/3 kept 1/3}
money = 1/3 spent + (36 = remaining 2/3)
money = 18 + 36
money = 54
tried to show you how I got it - hope it makes some sense
2006-08-15 18:40:13 · answer #5 · answered by Anonymous · 0⤊ 0⤋
1/3 is 12 dollars so 3/3 would be $36, the remainder. if that is 2/3, 1/3 would be 18. 18 * 3= $54 he must have worked at McDonalds.
2006-08-15 18:39:59 · answer #6 · answered by sllyjo 5 · 0⤊ 0⤋
he started with $24... as u see he spend 1/3 lost 2/3, meaning = 1
and its 12 .. after the spending and lost total he left 12 so its 24
2006-08-15 18:36:55 · answer #7 · answered by Anonymous · 0⤊ 0⤋
what's left = 1/3 of 2/3 of what he lost
what he lost = 12 * 3 = 36
$36 was what he had left after spending which is 2/3 now
therefore what he started with was 36/(2/3) = $54 VOILA!!!
2006-08-15 18:41:15 · answer #8 · answered by Anonymous · 0⤊ 0⤋
ThInk of it this way........
You must think about the fractions
The first thing is to resolve the 1/3 and 2/3 things
The question stipulates two fractions with denominators of 3!
The least submultiple you would be dealing with is 1/3/3= 1/9
Assume that the man had 9X intitiallly
He spent 1/3 of 9X i.e. 3X
So he was left with 9X - 3X = 6X
Of this, he lost 2/3, i.e. 4X
He was left with 6X - 4X = 2X
But you know 2X = $12, so, X = $6
AND,
The man strarted out with 9x6= 54 dollars!
Gwan, ahead!
2006-08-15 19:09:16 · answer #9 · answered by logikal 2 · 0⤊ 0⤋
he started with 54..
he had 54, spent 1/3 .
54/3=18.
so 54-18=36
1/3= 12.
2006-08-15 18:43:53 · answer #10 · answered by oneblondepilgrim 6 · 0⤊ 0⤋