why is 324 and 35,782,916 divisible by 4?

Question

Use what you know about the base 10 blocks to exp[lain why you only need to....

Answer 1

100 times any integer is divisible by 4. With your examples, you can break them up into 300 + 24 and 35,782,900 + 16 respectively. Having done that, all you have to look at is the last two digits.

Answer 2

START :

REM forget about the digits left of the 10's place (>99), since any multiple of 100 is divisible by 4.

divide the number by 100, until the remainder is less than 100
(modulo 100 division)

Check the remaning digits (10s' and units' number) by dividing by 20, if it is greater than 20 (modulo 20 division)

If the remainder is 0,4,8,12, 16, WHOA! it is divisible by 4
(to figure out why, ask another question and lose 5 marks!)

check 22,
remainder 2 ... Nyah

check 14,
remainder 14, (number is less than 20), no go!

try 24
remainder 4, part of the valid answer set

324= 3x100+24, hence divisible

35,782,916 = 357829 x 100+16,

if QED! then END else goto START

Answer 3

Both 324 and 35,782,916 are divisible by 4 because the last two numbers on each of the larger numbers are divisible by 4.

Answer 4

The rule of "4" ... if the last 2 digits are divisible by 4, then the number is divisible by 4, regardless of the size of the number.

Answer 5

I don't know the base 10 blocks, but both of the numbers last digit is 4. And any number is divisible by itself.

Answer 6

well you only have to look at the last two digits to determine if a number is divisible by 4 because 100, 200,300...all the way to 900 are all divisible by 4 so then you look at 24 and 16 and they are both divisible by 4

I don't know if that made sense but at least i tried to explain it

Answer 7

Because they are divisible by 4.

Answer 8

last two digits is divisible by 4

Answer 9

last two digits is divisible by 4

Answer 10

Everything is divisible by something except really odd occasions

Example: 11,33,77,99 etc,etc

All is divisible by 1 though --