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The only one i have found is 5 to the third power. are there any more?

2006-08-15 10:50:49 · 9 answers · asked by Susan F 2 in Science & Mathematics Mathematics

9 answers

5 ^ 4, 25 ^ 2, 125 ^ (4/3) , 390625^(1/2), ..... a lot of them

2006-08-19 02:38:24 · answer #1 · answered by Joe Mkt 3 · 1 0

You can find all the exponents by breaking down 625 into its prime factorization and combining all the elements of that factorization in various ways. 625's is 5*5*5*5, which means there's not a whole lot of exponents there. There's 5^4, 25^2, and 625^1 and that's pretty much it unless you're talking about stuff like 125*5^1.

2006-08-15 18:13:10 · answer #2 · answered by Kyrix 6 · 0 0

5^4 = 625 in base 10 is the only exponent

2006-08-15 17:58:22 · answer #3 · answered by gtn 3 · 0 0

Easy Solution:

5^4 = 625

Other Non-Integer solutions:

x^y = 625

y log(x) = log(625)

y = log(625)/log(x)


2^9.28771238 = 625

3^5.859894083 = 625

4^4.64385619 = 625

5^4 = 625 (for reference)

6^3.592977607 = 625

7^3.308349901 = 625

8^3.095904127 = 625

9^2.929947041 = 625

10^2.795880017 = 625

2006-08-15 18:06:13 · answer #4 · answered by ideaquest 7 · 0 0

25^2

2006-08-15 17:54:31 · answer #5 · answered by Anonymous · 0 0

625 is 5^4, n00b

2006-08-15 17:53:45 · answer #6 · answered by Anonymous · 0 0

I get 3:

5^4 4
25^2 2
625^1 1

If we're only considering integers.

2006-08-15 17:56:53 · answer #7 · answered by Dave 4 · 1 0

surely it is 5^4

as 5^3 is 125

so 5^4

or 25^2

2006-08-15 17:54:19 · answer #8 · answered by Orinoco 7 · 0 0

first... it's 5 ^ 4 not 5^3

or 25 ^2

the factors are 5 * 5 * 5 * 5

K?

2006-08-15 17:56:02 · answer #9 · answered by Anonymous · 0 0

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