5 ^ 4, 25 ^ 2, 125 ^ (4/3) , 390625^(1/2), ..... a lot of them
2006-08-19 02:38:24
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answer #1
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answered by Joe Mkt 3
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You can find all the exponents by breaking down 625 into its prime factorization and combining all the elements of that factorization in various ways. 625's is 5*5*5*5, which means there's not a whole lot of exponents there. There's 5^4, 25^2, and 625^1 and that's pretty much it unless you're talking about stuff like 125*5^1.
2006-08-15 18:13:10
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answer #2
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answered by Kyrix 6
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5^4 = 625 in base 10 is the only exponent
2006-08-15 17:58:22
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answer #3
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answered by gtn 3
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Easy Solution:
5^4 = 625
Other Non-Integer solutions:
x^y = 625
y log(x) = log(625)
y = log(625)/log(x)
2^9.28771238 = 625
3^5.859894083 = 625
4^4.64385619 = 625
5^4 = 625 (for reference)
6^3.592977607 = 625
7^3.308349901 = 625
8^3.095904127 = 625
9^2.929947041 = 625
10^2.795880017 = 625
2006-08-15 18:06:13
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answer #4
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answered by ideaquest 7
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25^2
2006-08-15 17:54:31
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answer #5
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answered by Anonymous
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625 is 5^4, n00b
2006-08-15 17:53:45
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answer #6
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answered by Anonymous
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I get 3:
5^4 4
25^2 2
625^1 1
If we're only considering integers.
2006-08-15 17:56:53
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answer #7
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answered by Dave 4
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surely it is 5^4
as 5^3 is 125
so 5^4
or 25^2
2006-08-15 17:54:19
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answer #8
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answered by Orinoco 7
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first... it's 5 ^ 4 not 5^3
or 25 ^2
the factors are 5 * 5 * 5 * 5
K?
2006-08-15 17:56:02
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answer #9
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answered by Anonymous
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